Answer:
100%
Explanation:
In this problem, we have one gene (pea color) with two possible alleles (green and yellow).
Green is dominant over yellow, so the possible genotypes and phenotypes are:
- GG or Gg = green pea pods
- gg = yellow pea pods.
If an individual is true breeding it is homozygous for all genes under study.
The cross between true breeding plants is:
<h3>GG x gg</h3><h3 />
The green parent (GG) can only produce <em>G </em>gametes; the yellow parent (gg) can only produce<em> g</em> gametes. 100% of the offspring will have the genotype Gg (green).
1. Avoid using phosphorus fertilizers and nitrogen fertilizers.
2. Avoid deforestration, and clearing of vegetation to increase the carbon sinks and decrease the atmospheric CO2 concentration.
3.Overall reduction in pollution
4.Reduce vehicular pollution
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Answer:
Quando uma célula somática se multiplica para dar origem a duas células-filhas, ela o faz a partir de um processo conhecido como mitose. Ou seja, as duas células-filhas mantém o mesmo número de cromossomos da célula-mãe.
The punnet square is
ii *IBI it equals IBi(all of them)
so it baby is heterogeneous B or IBi
Answer:
D) Changing the condition of the liver represents mechanical digestion; adding the hydrogen peroxide represents chemical digestion.
Explanation: