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3 years ago

7/11 as a decimal rounded to 3 decimal places

Mathematics

1 answer:

Scrat [10]3 years ago

5 0

Answer:

0.636

Step-by-step explanation:

7/11 we can times 11 by 100/11

Then times 7 by 100/11

then divide by 100

That gives us 0.636

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What is the next term of the geometric sequence? 2, -10, 50,

Anon25 [30]

To find the common ratio, divide the second term by the first term

-10 / 2 = -5

to find each term in a geometric sequence, u multiply by the common ratio.....
2 * -5 = -10
-10 * -5 = 50
50 * -5 = - 250 <== ur next term

3 0

3 years ago

A small city has three automobile dealerships: a GM dealer selling Chevrolets and Buicks; a Ford dealer selling Fords and Lincol

9966 [12]

Answer:

Event A = { Chevrolet , Buick }

Event B = { Ford , Lincoln }

Event C = { Toyota }

Step-by-step explanation:

- Mutually exclusive events are such that their probability of coming true simultaneously is zero. If we consider set notations we could say.

P (A & B) = P (B & C) = P (A & C) = 0

- In our case these events A,B, and C can be defined as:

Answer:

Event A = { Chevrolet , Buick }

Event B = { Ford , Lincoln }

Event C = { Toyota }

4 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$