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Pepsi [2]
3 years ago
11

Will mark brainly! 20 points please hurry and help!!

Mathematics
1 answer:
Nata [24]3 years ago
6 0
The correct answer is number one, number four, and number five. Please park Brainliest if helpful. Thanks
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Solve pls brainliest
zepelin [54]

Answer:

(1,6)

Step-by-step explanation:

all u gotta do is look at the graph, the school is at x=1 and y=6 so therefore (1,6)

5 0
3 years ago
Read 2 more answers
In 2002, the temperature on the first day of summer
Rina8888 [55]

Answer:

c

Step-by-step explanation:

86-6=80

5 0
4 years ago
Read 2 more answers
$ 425 is what percent more than $125 ?
Komok [63]

Answer:

240%

Step-by-step explanation:

100 x (425 - 125) / 125

3 0
2 years ago
Number of data values: 1007
kogti [31]

Answer:

The arithmetic mean is 10.9

Step-by-step explanation:

In this question, we are tasked with calculating the arithmetic mean using the information given.

The arithmetic mean or otherwise called the average is the sum of all the values in a given set divided by the number of elements or count of the elements in that particular data set

Mathematically, the arithmetic mean can be found by dividing the sum of the data values by the number of data values.

In equation form, we have Arithmetic -mean = \frac{sum of data values}{number of data values}

Inserting the values, we have Arithmetic mean = 10998/1007 = 10.92 which is 10.9 to the nearest tenth

5 0
3 years ago
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

                    =0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
3 years ago
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