Answer:
Step-by-step explanation:
given that a certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course:
We find
Mean 13.66666667 = 13.7
Standard Error 1.801234145
Margin of error for 90% = 1.645*std error = 2.963
Confidence interval = Mean ±Margin of error
=(10.704, 16.630)
Sample mean = 13.7
Is 9 an answer?
If it is I think 9
The mean of the data set 1 is 3.6 because if you add all the numbers up you’ll get 32/9 = 3.555555556 or 3.6
The mean of the data set 2 is 9.3 because if you add all the numbers up, you’ll get 93/10=9.3
Answer:
yes. y-=25x
Step-by-step explanation: