The <span>hardy-weinberg equation is
p2 + 2pq + q2 = 1
where are already given with
c = 0.1 and C = 0.9
SO
p2 = 0.9^2
p2 = 0.81
q2 = 0.01
0.81 + 2pq - 0.01 = 1
2pq = 0.18
The answers are
CC = 0.81
cc = 0.01
Cc = 0.18</span><span />
The answer is <span>Meiosis I.</span>
<span>Meiosis is a cell division which results in the reduction of chromosome
number by half - from diploid to haploid - in daughter cells. It consists
of meiosis I and meiosis II. Meiosis I produces two
haploid cells. Meiosis
II is analogous to mitosis, so each of these two haploid cells will in meiosis
II produce two haploid cells. In total, meiosis results in four haploid cells.</span>
<span>
</span>
<span>Therefore, the production of two haploid daughter cells is in meiosis I.</span>
Answer: The hepatic portal vein is one of the most important vein that receives blood from the body and transports it into the liver for filtration and processing. This vein is part of the hepatic portal system that receives all of the blood draining from the abdominal digestive tract, as well as from the pancreas, gallbladder, and spleen.
‘Hepatic’ means of or relating to the liver, therefore the hepatic portal vein is a blood vessel that sends nutrient-rich blood from the gastrointestinal tract and spleen to the liver, but also delivers toxins to the liver that will be chemically modified in the proces of detoxication
This type of asexual reproduction is called apomixis.
Apoximis is reproduction by special generative tissues without fertilization. It includes parthenogenesis in animals, in which the new individuals develop from unfertilized egg, and apogamy in certain plants in which the generative tissues may be the sporophyte or the gametophyte.
