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lions [1.4K]
4 years ago
6

ANSWER QUICKLY! Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2

, and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold. (QUESTION!!)
--->Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.
Mathematics
2 answers:
Temka [501]4 years ago
8 0

Answer:

2x+3y =1470

slope intercept form

y=mx+b

2x+3y =1470

subtract 2x from each side

3y = -2x+1470

divide by 3

y = -2/3 x +1470/3

y = -2/3x +490

slope = -2/3

y intercept = 490

Dafna1 [17]4 years ago
3 0

Answer:

y= -2/3x+490

slope: -2/3

y-intercept: 490

Step-by-step explanation:

Y-intercept form is y=mx+b, so you would first subtract 2x from both sides to get 3y= -2x+1,470. Then you divide both sides by 3, to get y= -2/3x+490. -2/3 is in the place of m, so it is the slope, and 490 is in the place of b, so it is the y-int.

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, Hayley sold 20 tickets to the school play for a total of $225 early bird tickets were $10 and regular price tickets were $15 w
Lady_Fox [76]

Answer:

15 early tickets were sold and 5 regular tickets were sold.

Step-by-step explanation:

Let x be the number of early bird tickets sold and y be the number of regular tickets sold.

Total number of tickets sold = 20

Thus, we can write the equation,

x + y = 20

Cost of early bird ticket = $10

Cost of regular tickets = $15

Total cost = $225

Thus, we can write the equation,

225 = 10x + 15y

We solve the equation by elimination method by multiplying first equation by 10 and subtracting.

10x + 15y-(10x+10y) = 225 - 200\\5y = 25\\\Rightarrow y=5\\x + 5 = 20\\\Rightarrow x = 15

Thus, 15 early tickets were sold and 5 regular tickets were sold.

5 0
3 years ago
How is the graph of y=4x^2+1 different from the graph of y=4x^2
ycow [4]
Assuming the first function is y = 4x2<span> + 1, and the second y = 4x</span>2<span> then the first graph is 1 unit higher than the second.</span>
3 0
4 years ago
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What is the distance between (-3,1) and (-2,-1) in units​
Nastasia [14]

Answer:

Here is the graph I made, starting from (-3,1) to (-2,-1) it goes down 2 units and over 1 unit.

6 0
3 years ago
Help please please please please please<br> 6th &amp; 7th
raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. log_a_ba=\frac{1}{3}

The first variable that I solved for was "a" and a=e^\frac{in(b)}{2}[tex]{[tex]  0}

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is a=\frac{1}{2} , b=\frac{1}{4}

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}}  )= -\frac{1}{18} and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. x=2,-2,\sqrt{2}, and -\sqrt{2} . (This does not account for any complex solutions)

Notice that the bases are conjugates which is why the answers are so "nice"

The key is in the exponents

if x^{2} -3 =1 then the sum on the conjugates will be 10 so

x^{2}-3=1
x^{2}=4
so x= 2 or -2

Now for the other two

the solution is also true if x^{2}-3=-1

so

x^{2}-3 = -1\\x^{2}=2\\x=\left \{ {{\sqrt{2}} \atop {-\sqrt{2}}} \right.

the four real solutions are 2, -2, \sqrt{2} ,-\sqrt{2}



6 0
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Find the lateral area of the prism.
Stels [109]
Okay since it's a right prism I assume you multiply the Perimeter times the height which looks to be 20x6 which would equal out to 120 as the lateral area.

(Sorry if I'm wrong, You're welcome if I'm right, Brainliest would be helpful and appreciated)  
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