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The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48
The given sequence is:
1,-1,-3, . . -13
and there are 8 terms.
The related series of this sequence is:
1-1-3-5- ... -13
Notice that the series is an arithmetic series with:
first term, a(1) = 1
common difference, d = -1 - (1) = -2
last term, a(8) = -13
To find the sum of the series, use the sum formula:
S(n) = n/2 [(a(1) + a(n)]
Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:
S(8) = 8/2 [1 + (-13)]
S(9) = 4 . (-12) = -48
Learn more about sum of a series here:
brainly.com/question/14203928
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It seems to me that the answer is c!<3
Answer:
the first option, (-4, 6)
Step-by-step explanation:
for this question, we can use the substitution method. this is where we substitute the coordinates in the answer choices into the given system of inequalities or equations to determine which one is true.
1. (-4,6)
x + 4y > 12
-4 + 4(6) > 12
20 > 12 is true
now we can substitute the second inequality.
3(6) > -4 + 6
18 > 2 is true, therefore making this set of points true.
it may be helpful to substitute the rest of the values of x and y into the inequalities to verify your answers :
5 + 4(2) > 12
5 + 8 > 12
13> 12 is true
3(2) > 5 + 6
6 > 11 is not true
the rest of the answer choices are also not true.
I hope this helped you!
