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vredina [299]
3 years ago
7

Tristan has found a good job as a bookkeeping clerk after finishing his associates degree at the local community college. He is

making a beginning annual salary of $19,760. How can this increased income affect his financial decisions? Compare his previous budget when he worked part time while finishing his degree with his current budget after getting a full time job.
Monthly budget | Previous Budget | Current Budget

income
Wages | $786 | $1646

Expenses
Rent | $300 | $600
Utilities | $60 | $120
Groceries | $130 | $200
Savings | $120 | $350
Car Expenses | $150 | $150
Entertainment | $20 | $120

Net Income | $6 | $106

a.Tristan is spending too much money on groceries and entertainment.

b.Tristan is earning quite a bit more in his full time job. He is spending more on rent, utilities, food, and entertainment, as well as saving $350 each month.

c.Tristan is earning double his previous wages. He should double his expenses, as well.

d.Tristan's increased income should have no effect on his financial decisions.
Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0

The increased income is affecting Tristan's financial decisions as now he is spending more as well as saving more.

The correct answer is option B.

Tristan is earning quite a bit more in his full time job. He is spending more on rent, utilities, food, and entertainment, as well as saving $350 each month.

stepladder [879]3 years ago
5 0

B. Tristan is earning quite a bit more in his full time job.

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An electric company charges a certain rate per kilowatt-hour (\text{kWh})(kWh)left parenthesis, start text, k, W, h, end text, r
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Step-by-step explanation:

The equation is given by :

63.25=800r+3.50

Here,

63.25 is the electric company charges

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In this proble, we need to tell that what does r represents. Hence, r shows kilowatt per hour.

We can solve it as follows :

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3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
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Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

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Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

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