Answer:
The angle will be "48.7°".
Step-by-step explanation:
In ΔTBO, the given values are:
TB = 6,000 feet
BO = 9,000 feet
Now,
To find the angle,
⇒ ![Cos \ B =\frac{TB}{BO}](https://tex.z-dn.net/?f=Cos%20%5C%20B%20%3D%5Cfrac%7BTB%7D%7BBO%7D)
On putting the estimated values, we get
⇒ ![Cos \ x=\frac{6000}{9000}](https://tex.z-dn.net/?f=Cos%20%5C%20x%3D%5Cfrac%7B6000%7D%7B9000%7D)
⇒ ![Cos \ x=0.66](https://tex.z-dn.net/?f=Cos%20%5C%20x%3D0.66)
⇒ ![x=Cos^{-1} \ 0.66](https://tex.z-dn.net/?f=x%3DCos%5E%7B-1%7D%20%5C%200.66)
⇒
Answer:
the difinition of addition is adding two things together
Step-by-step explanation:
Answer:
x=78
Step-by-step explanation:
q is 90 degrees since it is a right angle,
p=12
90 plus 12 =102
x=180-102
x=78
Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min