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3 years ago

Which type of reactions form salts?

Chemistry

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

Neutralization reactions

Explanation:

A neutralization reaction is a reaction between an acid and a base. Products of this type of reaction is water and a salt. The pH of the salt product would depend on how strong or weak the base and acid would be when they react with each other. Although the characteristics of bases and acids are practically polar opposites, when combined, they cancel each other our producing a neutralized product.

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The semi-conductors on the periodic table are classified as

Mila [183]

Most likely the transition metals

4 0

4 years ago

Magnesium burns in air with a dazzling brilliance to produce magnesium oxide: 2 Mg(s) + O2(g) → 2 MgO(s) How many moles of O2 ar

TEA [102]

Answer:

1.05 mols of O2 gas

Explanation:

For this type of problem, it's important to understand what the balanced Chemical equation tells us:

<h3><u>Balanced Chemical equations</u></h3>

Let's look at the balanced chemical equation:

$2Mg(s)+O_2(g)-- > 2MgO(s)$

This equation two sides of the reaction arrow. On the left are the reactants (things you start with, and that react during the chemical reaction), and on the right side are products (things that are produced during the chemical reaction that you end with).

The numbers in front of each compound tell how many of molecules are involved for a full reaction without anything left over. A "mol" is a large quantity ( $6.022*10^{23}$ ), in this case, of molecules , since it's unlikely you're only taking a single molecule of each substance (it would be so tiny, you wouldn't even know you were doing the reaction).

So,for every 2 moles of Magnesium used, we'll also need 1 mole of Oxygen, and it will produce 2 moles of Magnesium Oxide.

In a way, during the reaction it's almost like 2 moles of Magnesium is equal to 1 mole of Oxygen and is equal to 2 moles of Magnesium Oxide:

$2 mol Mg(s)=1mol O_2(g)=2molMgO(s)$

From here, we can build some unit ratios, to convert between the known quantity of moles we have, and find the unknown quantity of moles that are requested.

<h3><u>Finding the right unit ratio</u></h3>

We know that we are looking at 2.10 mol of Magnesium, so we want a unit ratio with moles of Mg on the bottom. <u>We want to find moles of O2</u>, <u>so we want a unit ratio of moles of O2 on top</u>.

The unit ratio we want is the middle part of the equation, divided by the left part of the equation.

$2 mol Mg(s)=1mol O_2(g)\\\frac{2 mol Mg(s)}{2 mol Mg(s)}=\frac{1mol O_2(g)}{2 mol Mg(s)}\\1=\frac{1mol O_2(g)}{2 mol Mg(s)}$

Since this quantity is 1, it is a unit ratio and can be multiplied to other things to change their units (for this problem).

<h3><u>Finding the answer</u></h3>

Starting with what we know, and multiplying by our unit ratio:

$2.10 mol Mg(s)*\frac{1mol O_2(g)}{2 mol Mg(s)}=1.05mol O_2(g)$

Notice that the units from the first quantity cancel with the units on the bottom of the fraction, leaving only the unit on top of the fraction ... the exact units we wanted!

So, 1.05mols of O2 would be consumed during the reaction if exactly 2.10moles of Magnesium are burned.

4 0

3 years ago

Explain how the understanding of atomic emission spectrum lead to development of the atomic theory

kiruha [24]

here we have to explain the development of the atomic theory by the atomic emission spectrum.

The most important aid in determining the structure of an atom has been study of radiation emitted and absorbed by the elements. The glowing atoms of an element emit radiations.

These are called the atomic spectra. This study helped to understand the structure of the atoms.

To explain the atomic spectra the Bohr's model was introduced. The postulates of the Bohr's model explain the fine spectrum of the atom up to the particle nature of the electrons.

Later some modification on the Bohr's postulates was made to explain the wave nature of the electrons as well. But the atomic spectra is best be understood by the Bohr's atomic model which developed the atomic theory.

Thus the understanding of emission spectrum of atom to develop the atomic theory is explained.

8 0

4 years ago

Karla added green pellets to a container of water before she began watering her lawn. What correctly describes

kvv77 [185]

The correct answer is C. The water is the solvent because the green pellets dissolved in it.

Explanation:

In solutions, the are two substances involved, the solvent and the solute. The solvent is usually a liquid substance; additionally, the solvent dissolves another substance, which is known as the solute. For example, if you dissolve a spoon of salt in a glass of water, the solute is the salt which is the substance dissolved and the solvent is the water because the solute is dissolved in it. According to this, in the case presented the water is the solvent because the green pellets which are the solute dissolve in it.

5 0

4 years ago

What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon

Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles$

$\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles$

$Al_2O_3+3C\rightarrow 2Al+3CO$

According to stoichiometry :

1 mole of $Al_2O_3$ require 3 moles of $C$

Thus 0.59 moles of $Al_2O_3$ will require= $\frac{3}{1}\times 0.59=1.77moles$ of $C$

Thus $Al_2O_3$ is the limiting reagent as it limits the formation of product and $C$ is the excess reagent as it is present in more amount than required.

As 1 mole of $Al_2O_3$ give = 2 moles of $Al$

Thus 0.59 moles of $Al_2O_3$ give = $\frac{2}{1}\times 0.59=1.18moles$ of $Al$

Mass of $Al=moles\times {\text {Molar mass}}=1.18moles\times 27g/mol=31.8g$

Thus 31.8 g of $Al$ will be produced from the given masses of both reactants.

5 0

3 years ago