Answer:
265.2amu
Explanation:
Given parameters:
Atomic mass = 254.9amu
Abundance of isotope 1 = 72%
Atomic mass of isotope 1 = 250.9amu
Abundance of isotope 2 = 100 - 72 = 28%
Unknown:
Atomic mass of isotope 2 = ?
Solution:
To find the atomic mass of isotope 2, use the expression below:
Atomic mass = (abundance of isotope 1 x atomic mass of isotope 1) + (abundance of isotope 2 x atomic mass of isotope 2)
Now insert the parameters and find the unknown;
254.9 = (0.72 x 250.9) + (0.28 x Atomic mass of isotope 2)
254.9 = 180.648 + 0.28x atomic mass of isotope 2
254.9 - 180.648 = 0.28x atomic mass of isotope 2
74.25 = 0.28 x atomic mass of isotope 2
Atomic mass of isotope 2 = 265.2amu
Answer:
Physical change is a temporary change. A chemical change is a permanent change.
Explanation:
A Physical change affects only physical properties i.e. shape, size, etc. Chemical change both physical and chemical properties of the substance including its composition.
The answer is <span>0.000261 millimeters</span>
5.911 grams of manganese dioxide and 1.224 gram of water are consumed.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given reaction balanced equation is:
Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)
<h3>How to find the number of moles ?</h3>
To find the number of moles use the expression:
Number of moles =
Here,
Mass of Zn = 4.50 g
Molar mass of Zn = 65.4 g/mol
Now put the value in above expression
Number of moles of Zn =
=
= 0.068 mol
Mass of MnO₂ = Moles of MnO₂ × Molar mass of MnO₂
= 0.068 mol × 86.9368 g/mol
= 5.911 g
Mass of H₂O = Moles of H₂O × Molar mass of H₂O
= 0.068 mol × 18.0 g/mol
= 1.224 g
Thus from the above conclusion we can say that 5.911 grams of manganese dioxide and 1.224 gram of water are consumed.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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Elements get heavier as the periodic table progresses down the line.