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Anit [1.1K]
3 years ago
15

In a blast furnace, elemental iron is produced from a mixture of coke (c), iron ore (fe3o4), and other reactants. an important r

eaction sequence is 2c(s) + o2(g) ? 2co(g), fe3o4(s) + 4co(g) ? 3fe(l) + 4co2(g). how many moles of iron can be formed in this sequence when 1.00 mol of carbon, as coke, is consumed?
Chemistry
1 answer:
jok3333 [9.3K]3 years ago
5 0

Reaction sequence:

2c(s) + o2(g) -> 2co(g)

fe3o4(s) + 4co(g) -> 3fe(l) + 4co2(g)

According to first equation, 2 moles of carbon produce 2 moles of carbon monoxide. So 1 mole of carbon will produce 1 mol of carbon monoxide (the same number).

According to the second equation, 4 moles of carbon monoxide produce 3 moles of iron. We should make the cross multiplication with those numbers:

4 moles CO/3 moles iron = 1 mol CO/x

x = 1 mol CO*3 moles iron/4 moles CO = 0.75 moles of iron

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2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
Hwlp meeeeeeeeeeeeeeeeeeee
Vanyuwa [196]
The most appropriate answer is C !!
4 0
3 years ago
if 15 mol C is mixed with 10 mol O2 which reactant is the limiting reactant? Which reactant would be the excess reactant?
ioda

Answer:

C is the excess reactant.

Explanation:

Reaction is C + O2 --> CO2

1mol of C required to react with 1mol O2

Therefore 15 - 10 = 5moles of C will be in excess

6 0
3 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
2 years ago
Which compound contains a triple bond?
Masteriza [31]

Answer: C2H2

Explanation: Because each of the lines represent one bond, and because there are three lines (bonds) between the carbons, it means that they are bonded by three bonds, also known as a triple bond.

5 0
3 years ago
Read 2 more answers
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