Question

A? twin-engined aircraft can fly 1064 miles from city A to city B in 4 hours with the wind and make the return trip in 7 hours against the wind. What is the speed of the? wind?

Answer 1

Answer:

Wind speed = 159.6 miles per hour.

Step-by-step explanation:

The distance is the same so some sort of basic equation can be made.

Givens

From A to B

t = 4 hours

v = p + w

d = 1064

===========

From B to A

t1 = 7 hours

v = p - w

d = 1064

Equation

t * (p + w) = t1 * ( p - w)

Solution

4(p + w) = 7(p - w)

4p + 4w = 7 p - 7w

Add 7w to both sides.

4p + 4w + 7w = 7p

4p + 11w = 7p    

Subtract 4p from both sides

11w = 7p - 4p

11w = 3p

Divide by 3

p = 11w/3

====================

4P + 4W = 1064

11w/3 + 3W = 1064

w(3.6667 + 3) = 1064

W*6.666667 = 1064

W = 1064 / 6.666667

W = 159.6 mph