All categories

4 years ago

What is the equation from(2,32) to (38,40

1 answer:

4 0

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{32})\qquad (\stackrel{x_2}{38}~,~\stackrel{y_2}{40}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{40}-\stackrel{y1}{32}}}{\underset{run} {\underset{x_2}{38}-\underset{x_1}{2}}}\implies \cfrac{8}{36}\implies \cfrac{2}{9}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{32}=\stackrel{m}{\cfrac{2}{9}}(x-\stackrel{x_1}{2})\implies y-32=\cfrac{2}{9}x-\cfrac{4}{9} \\\\\\ y=\cfrac{2}{9}x-\cfrac{4}{9}+32\implies y=\cfrac{2}{9}x\implies +\cfrac{284}{9}$

You might be interested in

The table shows the distance that two trains are from center station at various times of the day

VLD [36.1K]

Answer: Train 2 is traveling 4 miles per hour faster than train 1.

Hope this helps..... Stay safe and have a Merry Christmas!!! :D

3 0

3 years ago

BAC ~ DEC<br><br>x = ___ units

sergey [27]

Given:

$\Delta BAC\sim \Delta DEC$

To find:

The value of x.

Solution:

We have,

$\Delta BAC\sim \Delta DEC$

The corresponding parts of similar triangles are proportional.

$\dfrac{AB}{ED}=\dfrac{AC}{EC}$

On substituting the values, we get

$\dfrac{24}{56}=\dfrac{2x}{3x+5}$

$\dfrac{3}{7}=\dfrac{2x}{3x+5}$

$3(3x+5)=2x(7)$

$9x+15=14x$

Subtract $9x$ from both sides.

$15=14x-9x$

$15=5x$

$\dfrac{15}{5}=x$

$3=x$

Therefore, the value of x is 3 units.

4 0

3 years ago

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.

Wittaler [7]

Answer 12.5 < x 18.9

7 0

3 years ago

Calculate the difference between double 50 and half of 80

Alborosie

Answer:

Step-by-step explanation:

double 50 is 100 half of 80 is 40 answer is 60

hope this helps

6 0

3 years ago

V / -0.8 +14=39 plssss help this is literally so hard

Nat2105 [25]

<h2><u>Answer:</u></h2><h2> $\boxed{\boxed{\sf~v=-20}}$ </h2><h2 /><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Subtract 14 from both sides:</h3>

$14-14=$ Cancels Out

$39-14=25$

<em> - We do this because we have to get 2 variables/numbers on each side of the equals, and the only way to do so is to cancels other numbers out by doing the opposite of what we see. </em>

<u>Equation at the end of Step 1: </u>

$v$ ÷ $-0.8=25$

<h3>2.) Multiply both sides by −0.8:</h3>

$-0.8$ × $-0.8=$ Cancels Out

$25$ × $-0.8=-20$

______________________________

3 0

3 years ago