Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}
iren [92.7K]
Answer:
A) a_n = 5n + 2
B) a_n = (2^(n + 1)) - 1
Step-by-step explanation:
A) The sequence is given as;
{7,12,17,22,27,...}
The differences are:
5,5,5,5.
This is an arithmetic sequence following the formula;
a_n = a_1 + (n - 1)d
d is 5
Thus;
a_n = a_1 + (n - 1)5
Now, a_1 = 7. Thus;
a_n = 7 + 5n - 5
a_n = 5n + 2
B) The sequence is given as;
{ 3,7,15,31,63,...}
Now, let's write out the differences of this sequence:
Differences are:
4, 8, 16, 32
This shows that it is a geometric sequence with a common ratio of 2.
In the given sequence, a_1 = 3 and a_2 = 7 and a_3 = 15
Thus, a_2 = 2a_1 + 1
Also, a_(2 + 1) = 2a_2 + 1
Combining both equations, we can deduce that: a_(n + 1) = 2a_n + 1
Thus; a_n can be expressed as:
a_n = (2^(n + 1)) - 1
The x shows how they are meeting with the things to be with
Grant needs to ride at least 13.33 miles to male at least $ 15.00 a day
<em><u>Solution:</u></em>
Given that Grant has an agreement with Brian to rent the bike for $35.00 a night
He charges customers $3.75 for every mile he transports them
Grant needs to make at least $15.00 a day
To find: miles needed to ride
From given question, He charges customers $3.75 for every mile he transports them
So if he transports for "x" miles he would get,

So the profit he gets is $ 3.75 and initial cost invested to rent bike is $ 35. Also, Grant needs to make at least $15.00 a day
So we can frame a inequality as:

So he needs to ride atleast 13.33 miles to male atleast $ 15.00 a day
Let, the number = x
It would be: x * 0.32 = 16
x = 16 / 0.32
x = 50
In short, Your Answer would be 50
Hope this helps!
1. Answer:
30 is your frequency
Step-by-step explanation:
Frequency in this case would be the number of winners. So to find the frequency we would need to add up the total number of winners in the histogram.
So, 0 + 2 + 5 + 6 + 8 + 5 + 4 = 30
2. Answer:
6 (you already put that)
3.
The median can be found in the 50-59 bin or interval.