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Lelu [443]
3 years ago
14

The value of 29.94 ×0.5 is approximately

Mathematics
1 answer:
lilavasa [31]3 years ago
5 0
Answer: 14.97
That is the exact answer
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Graph y= –3x+4 k12<br> im practing for a test can i get this in picture form
Svetradugi [14.3K]

<em>Figure represented the line y = -3x+4</em>

Step-by-step explanation:

Given y=-3x+4 is equation of line

In order to graph the line, we need atleast two points

Now, When x = 0, y=?

y = -3x+4

y = -3(0) +4

y = 4

Point we get A(0,4)

Now, When x = 1, y=?

y = -3x+4

y = -3(1)+4

y = -3+4 = 1

Point we get B(1,1)

On graph, Locate points A(0,4) and B(1,1)

Draw a line passing through both of the points at once.

Figure is shown for your reference.

7 0
3 years ago
ASAP!!! PLEASE help me with this question!
Aloiza [94]
Pretty sure it’s a circle , why would it be a rectangle and a right angle
6 0
3 years ago
60% of what number is 75
kramer
60\% \ of \ x =75 \\\\ \frac{60}{100}*x=75\\\\ \frac{6}{10}=\frac{75}{x} \\\\ \frac{3}{5}*\frac{75}{x} \\\\ x=\frac{5*75}{3} \\\\ x=5*25 \\\\ \boxed{x=125}
8 0
3 years ago
Help please i am stuck
BaLLatris [955]

Answer:

x = 25

Angle B = 65 degrees

Angle C = 50 degrees

Step-by-step explanation:

All triangles will add up to 180 degrees.

65 + 3x - 10 + 2x = 180

Combine like terms

55 + 5x = 180

Subtract both sides by 55

5x = 125

Divide both sides by 5

x = 25

Plug in the value for x in angle B:

3(25) - 10

75 - 10

65

Do the same for angle C:

2(25)

50

Check your work:

65 + 65 + 50 = 180

180 = 180

Correct

6 0
3 years ago
Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two
Tom [10]

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333

The sum of these x -coordinates is \frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, 3x + 27x^2=2 and we solve for x

3x+27x^2-2=2-2\\27x^2+3x-2=0\\\left(27x^2-6x\right)+\left(9x-2\right)\\3x\left(9x-2\right)+\left(9x-2\right)\\\left(9x-2\right)\left(3x+1\right)=0

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

9x-2=0\\9x=2\\x=\frac{2}{9}

3x+1=0\\3x=-1\\x=-\frac{1}{3}

The solutions are:

x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333

The sum of these x -coordinates is

\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}

We can check our work with the graph of the two polynomials.

4 0
4 years ago
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