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3 years ago

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Jonah is thinking of a two digit number. It is a multiple of 6 and 12. It is a factor 108. The sum of his digits is 9. What numb

er is jonah thinking of?

1 answer:

erik [133]3 years ago

3 0

The answer is 36. 36 is two digits, 3 and 2, it is a multiple of 6 and 12: 6 times 6 equals 36 and 12 times 3 equals 36, it is a factor of 108: 36 times 3 equals 108, and 36 has digits that equal to 9: 3 plus 6 equals 9.

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Find the perimeter <br> Simplify your answer completely

Lubov Fominskaja [6]

Answer:

4/2+ 8/2+20/5+20/5+48/5+42/4

12/2+88/5+42/4

(120+ 352+210)/20= 682/20= 341 x 1/10=34.1

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3 years ago

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Kevin is 333 years older than Daniel. Two years ago, Kevin was 444 times as old as Daniel.

tia_tia [17]

Answer: the equations are

k = d + 33

k - 2 = 4(d-2)

Step-by-step explanation:

Let the present age of Kevin be represented by k

Let the present age of Daniel be represented by d

Kevin is 33 years older than Daniel. This means that the expression for their current age is

k = d + 33

Two years ago, Kevin was 4 times as old as Daniel. This means that 2 will be subtracted from their present ages to depict two years ago. Therefore, Two years ago for Daniel will be d-2

Two years ago for Kevin will be k - 2

Remember that Kevin was 4 times as old as Daniel two years ago, it becomes

k - 2 = 4(d-2)

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3 years ago

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9 to the power 3 + 3 to the power 2 + 6 to the power 3 + 15 power 2 equals to how much

Llana [10]

Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!

So-------

9^3=729

3^2=9

6^3=216

15^2=225

Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.

Therefore, your final answer will be 1,174.

If you have any questions on this, I'm happy to help you. :)

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3 years ago

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For what values (cases) of the variables the expression does not exist: a a 2x−4

Natasha2012 [34]

Step-by-step explanation:

When the denominator is zero, the expression is undefined

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x=2

5 0

3 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

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3 years ago