You've got five different problems in this photo ... four on top and the word problem on the bottom ... and they're all exactly the same thing: Taking two points and finding the slope of the line that goes through them.
In every case, the procedure is the same.
If the two points are (x₁ , y₁) and (x₂ , y₂) , then
the slope of the line that goes through them is
Slope = (y₂ - y₁) / (x₂ - x₁) .
This is important, and you should memorize it.
#1). (8, 10) and (-7, 14)
Slope = (14 - 10) / (-7 - 8) = 4 / -15
#2). (-3, 1) and (-17, 2)
Slope = (2 - 1) / (-17 - -3) = (2 - 1) / (-17 + 3) = 1 / -14
#3). (-20, -4) and (-12, -10)
Slope = [ -10 - (-4) ] / [ -12 - (-20) ]
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The word problem:
This question only gives you one point on the graph,
and then it wants to know what's the slope ?
What are you going to do for another point ?
A "proportional relationship" always passes through the origin,
so another point on the line is (0, 0) .
Now you have two points on THAT line too, and you can easily
find its slope.
Answer:
18¾ ft × 15 ft
Step-by-step explanation:
The dimensions of the billboard are 25 ft by 15 ft.
The dimensions of the image are 5 ft by 4 ft
Case 1.<em> Expand the length of the image to 25 ft.
</em>
We have multiplied the length by five, so we must multiply the width by five.
w = 5 × 4 = 20 ft. That's too big. The image will overflow the billboard
by 5 ft.
<em>Case 2. </em><em>Expand the width of the image to 15 ft.
</em>
We have multiplied the width by 15/4, so we must multiply the length by 15/4.
l = 15/4 × 5 = 75/4 = . That will fit, with 6¼ ft left over.
The expanded image will be 18¾ ft × 15 ft.
In the image below, the big rectangle represents the billboard, and the red rectangle represents the original image.
The pink rectangle represents the dilation of the original image to a width of 15 ft.
I think the volume is 200
Answer:
(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.
(b) Every function of the form
is an antiderivative of 8x
Step-by-step explanation:
A function <em>F </em>is an antiderivative of the function <em>f</em> if

for all x in the domain of <em>f.</em>
(a) If
, then
is an antiderivative of <em>f </em>because

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.
Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.
(b) Because

then
is an antiderivative of
. Therefore, every antiderivative of 8x is of the form
for some constant C, and every function of the form
is an antiderivative of 8x.