Question

6.31 LAB: Leap year - functions A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is:

Answer 1

Answer:

The code is given below in C with appropriate comments

Explanation:

#include <stdio.h>

#include <stdbool.h>

bool ISLeapYear(int userYear)

{

  // If a year is multiple of 400,

  // then it is a leap year

  if (userYear % 400 == 0)

      return true;

  // Else If a year is multiple of 100,

  // then it is not a leap year

  if (userYear % 100 == 0)

      return false;

  // Else If a year is multiple of 4,

  // then it is a leap year

  if (userYear % 4 == 0)

      return true;

  return false;

}

int main(void) {

  int year;

  printf("Enter year : ");

  scanf("%d",&year);

  if(ISLeapYear(year)){

      printf("%d is a leap year.",year);

  }else{

      printf("%d is not a leap year.",year);

  }

  return 0;

Answer 2

Answer:

#include <iostream>

using namespace std;

int main()

{

   int detect_year;

   cout << "Enter a year to find whether its leap year or not: ";

   cin >> detect_year;

   if (detect_year % 4 == 0)

   {

       if (detect_year % 100 == 0)

       {

           if (detect_year % 400 == 0)

               cout << "The year you entered "<< detect_year << " is a leap year.";

           else

               cout << "The year you entered "<<detect_year<< " is not a leap year.";

       }

       else

           cout << "The year you entered "<< detect_year << " is a leap year.";

   }

   else

       cout << "The year you entered "<<detect_year<<" is not a leap year.";

   return 0;

}

Explanation:

first make a variable named as detect_year of time integer. The using cin ask the user to enter any year to find out whether its leap year or not. Once the user has entered the year the value is stored in detect_year variable. After the divide the year by 4 if the remainder is not zero then it is not a leap year. If it is divisible by 4 which means the remainder is zero the divide the year by 100. If the remainder is not zero means it is not divisible by 100 then its a leap year. If it is divisible by 100 then check whether the year is divisible by 400 if yes then it is leap year other wise it is not.