Because when you subtract a negative number the signs cancel out and become and addition problems
Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
Answer:
<h2>122.5</h2>
Step-by-step explanation:
the parameter of B figure is
12+9+9+5
35
as we know the scale factor is 7/2
so the parameter of A figure is
35×7/2
122.5
Then, now that we have solved for T, we can evaluate and solve for t=20 minutes.
