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ruslelena [56]
3 years ago
12

Why are chemical reactions often carried out using solutions? The heterogenous nature of solutions prevents the reactants from f

reely mixing. The amount of each reactant can be controlled by adjusting the volume of each solution that is used. Even very small amounts of reactants can be combined by using dilute solutions. A color change will always occur when a reaction is conducted in solution. The molecules or ions in a solution can freely intermingle. The solvent must always be water, so it is impossible for a fire to start.
Chemistry
1 answer:
baherus [9]3 years ago
7 0

Answer:

The molecules or ions in a solution can freely intermingle.  

Explanation:

The reactant molecules and ions can move freely in solution, so thy are more likely to collide with each other and form products.

A is wrong. Solutions are homogeneous.

B and C are wrong. The statements are correct, but they are not the reason why reactions are carried out in solution.

D is wrong. Chemical reactions do not always produce a colour change.

F is wrong. Some chemicals react with water, so other (often flammable) solvents must be used.

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tert-Butyl alcohol is a solvent with a Kf of 9.10 ∘C/m and a freezing point of 25.5 ∘C. When 0.807 g of an unknown colorless non
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Answer:

ethylene glycol (molar mass = 62.07 g/mol).

Explanation:

  • We can solve this problem using the relation:

<em>ΔTf = Kf.m,</em>

ΔTf is the depression in the freezing point of tert-Butyl alcohol (ΔTf = freezing point of pure solvent - freezing point in presence of unknown liquid = 25.5°C - 15.3°C = 10.2°C).

Kf is the molal freezing point constant of tert-Butyl alcohol (Kf = 9.1 °C/m).

m is the molality of unknown liquid.

∵ ΔTf = Kf.m

<em>∴ m = ΔTf/Kf </em>= (10.2°C)/(9.1 °C/m) = <em>1.121 m.</em>

  • We need to calculate the molar mass of the unknown liquid:

Molality (m) is the no. of moles of solute in 1.0 kg of solvent.

∴ m = (mass/molar mass) of unknown liquid/(mass of tert-Butyl alcohol (kg))

m = 1.121 m, mass of unknown liquid = 0.807 g, mass of tert-Butyl alcohol = 11.6 g = 0.0116 kg.

<em>∴ molar mass of unknown liquid = (mass of unknown liquid)/(m)(mass of tert-Butyl alcohol (kg)) </em>= (0.807 g)/(1.121 m)(0.0116 kg) = <em>62.06 g/mol.</em>

<em></em>

  • So, the unknown liquid is:

<em>ethylene glycol (molar mass = 62.07 g/mol).</em>

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