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Gnom [1K]
3 years ago
6

Predict how maritime air masses would change if the ocean froze

Chemistry
1 answer:
MrRissso [65]3 years ago
3 0

Air moves from

high(pressure)the regions at the

poles(d0)

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Someone plsss help me I will make you as brain plsss
Helga [31]

Answer:

2 only

Explanation:

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2 years ago
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An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0
3 years ago
Avnew moon is when the Moon is completely dark, and usually can't be seen.
dexar [7]

Answer:

A. In Four Weeks

Explanation:

8 0
3 years ago
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34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
3 years ago
When an atom of n-14 is bombarded by an alpha particle, the single product is?
aliya0001 [1]
For the answer to the question above asking w<span>hen an atom of n-14 is bombarded by an alpha particle, the single product is?

</span> <span>You're starting with 14/7 N, correct? 

An alpha particle is two protons, two neutrons, which is 4/2, correct? 
</span><span>So I</span> think the answer to your question is the third one which is <span>c. 18/9 f </span>
4 0
3 years ago
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