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Eva8 [605]
3 years ago
9

¿sabes cual es la concentración de azúcar en un refresco de un litro?​

Chemistry
1 answer:
Grace [21]3 years ago
8 0
“Esto quiere decir que en una lata de 330 ml tiene alrededor de 36 gramos de azúcar, mientras que una botella de 1 l tendrá 110 gramos”

110 gramos
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Which of the following is the number of moles of solute that is dissolved in 1 liter of solution?
Komok [63]
I believe the correct answer is option B. Molarity is the <span>number of moles of solute that is dissolved in 1 liter of solution. It is another way of expressing concentration of a mixture especially for solutions. Percent by mass is grams solute per grams of solution. Percent by volume is liter solute per liter per solution.</span>
4 0
3 years ago
An astronaut has a mass of 60kg. Calculate their weight When they are on the surface of the moon.
IceJOKER [234]

Answer:

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7 0
3 years ago
Hello people ~
Natalija [7]

Answer:

Opposes the motion

Explanation:

Let's take an example

  • Suppose you kicked a ball and the ball is doing down the ground
  • The friction makes the ball to stop after sometime .
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option A is correct

8 0
3 years ago
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dem82 [27]
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8 0
3 years ago
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
3 years ago
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