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Molodets [167]
3 years ago
8

The length of a rectangular field is 7 m less than 4 times the width. The perimeter is 136m ?. Find the width and the length of

the rectangle
Mathematics
1 answer:
elixir [45]3 years ago
7 0
<h3> ♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The perimeter is the total of all the lengths / widths

The lengths can be represented by 4x - 7

The width can be represented by x

2 times the length + 2 times the width would equal the perimeter

2(x) + 2(4x - 7) = 136

Simplify:

2x + 8x - 14 = 136

10x - 14 = 136

Add 14 to both sides:

10x = 150

Divide both sides by 10:

x = 15

The width is equal to 15m

The length is 4(15) - 7 = 53m

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Answer:

8t^3-36t^2+54t-27

Step-by-step explanation:

(2t-3)^3

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Multiply

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Answer:

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Step-by-step explanation:

To solve this equation, we need the formula for perfect squares:

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or

  • (a - b)^2 = a^2 - 2ab + b^2 <em>this is the formula we will use because the signs match the one in the question</em>.

Knowing these, we can set up an equation that assumes that the answer we will end up with is a perfect square.

Work:

(v - x)^2 = v^2 -8v + x^2

  • this is the setup for being able to solve for the unknown x, now we need to solve for x.

(v - x)^2 = v^2 - 8v + x^2 (I replaced 2ab with 8v because I'm setting up this question to be a perfect square).

(v - x) (v - x) = v^2 - 8v + x^2

  • multiply the left side. Remember that your answer will not be v^2 + x^2, but v^2 - 2vx +x^2.

v^2 - 2vx + x^2 = v^2 + 8v + x^2

  • Divide like terms and isolate the variable. In this case, v^2 and x^2 are on both sides, so dive them and they will be canceled out.

2vx = 8v

  • divide by 2v and you will have your value for x.

x = 4

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(v - 4)^2 = v^2 - 8v + 16

Our final answer is 16.

5 0
4 years ago
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Answer:

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