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kykrilka [37]
3 years ago
6

When x is between -4 and -1, is the function increasing or decreasing

Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Given: F(x) = x/ x^2-9

Graph-

graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%2F%28x%5E2-9%29%29

f. Is the function increasing or decreasing in the interval -3<- x <- 3?

Check the graph.

g. As x approaches 3 from the left, what happens to the function values?

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Solve the equation show your work 3x equals 45​
natima [27]

Answer:

x = 15

Step-by-step explanation:

3x / 3 = 45 / 3 x = 15

7 0
3 years ago
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Write n+6 in a word phase
Delvig [45]
The sum of a number and 6.

Or

The sum of n and 6
7 0
3 years ago
The coordinates of A and B are given
mash [69]
Answer to part 1 is 2/6 for the slope(or gradient) of the line

4 0
3 years ago
What is the arithmetic rule to the sequence: <br>1/3,4/3,7/3<br><br>find: f(10)
makkiz [27]

The the value of f(n)=\frac{28}{3}

Step-by-step explanation:

The Arithemetic sequence is given as a,a+d,a+2d......a(n-1)d

and f(n)=a(n-1)d

The given sequence is 1/3,4/3,7/3...

By comapring with Arithemetic sequence,

we get a=1/3

a+d=4/3

1/3 + d = 4/3

d=1

To find value of f(10):

take n=10

f(n)=\frac{1}{3} +(10-1)1

f(n)=\frac{1}{3} +(9)1

f(n)=\frac{1+27}{3}

f(n)=\frac{28}{3}

8 0
3 years ago
Quick Computing Company produces
olganol [36]

Answer:

c(x) = 2x^2 + 6x + 25

Completed question;

Quick Computing Company produces calculators. They have found that the cost, c(x), of making x calculators is a quadratic function in terms of x. The company also discovered that it costs $45 to produce 2 calculators, $81 to produce 4 calculators, and $285 to produce 10 calculators. Derive the function c(x).

Step-by-step explanation:

Given that;

the cost, c(x), of making x calculators is a quadratic function in terms of x.

c(x) = ax^2 + bx + c

Substituting the 3 case scenarios given;

it costs $45 to produce 2 calculators,

45 = a(2^2) + b(2) + c

45 = 4a + 2b +c .......1

$81 to produce 4 calculators,

81 = a(4^2) + b(4) + c

81 = 16a + 4b + c .......2

and $285 to produce 10 calculators.

285 = a(10^2) + b(10) + c

285 = 100a + 10b + c .......3

Solving the simultaneous equation;

Subtracting equation 1 from 2, we have;

36 = 12a + 2b ......4

Subtracting equation 1 from 3

240 = 96a + 8b .......5

Multiply equation 4 by 4

144 = 48a + 8b ......6

Subtracting equation 6 from 5, we have;

96 = 48a

a = 96/48

a = 2

Substituting a = 2 into equation 4;

36 = 12(2) + 2b

36 = 24 + 2b

2b = 36-24 = 12

b = 12/2 = 6

b = 6

Substituting a and b into equation 1;

45 = 4(2) + 2(6) +c

45 = 8 + 12 + c

c = 45 - (8+12)

c = 25

Since a = 2 , b = 6 and c = 25, the quadratic equation for c(x) is ;

c(x) = ax^2 + bx + c

c(x) = 2x^2 + 6x + 25

5 0
3 years ago
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