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jolli1 [7]
3 years ago
5

Which the following is an example of an organic compound that contains an attached carbonyl group at the end of a carbon chain?

Chemistry
2 answers:
Oksanka [162]3 years ago
5 0
Most likely the organic compound that contains a carbonyl group bonded near to the end of the chain would be an aldehyde. Unlike a ketone where the carbonyl can be found anywhere within the chain, an aldehyde, is specifically found near the end of the compound, because it would be bonded to H as well.
andrey2020 [161]3 years ago
4 0

Answer : The correct option is, Aldehyde.

Explanation :

Ketone group : It is the class of organic compound in which the -CO group is attached to a hydrocarbon is known as ketone.

The general representation of ketone are, R-CO-R'.

For example : Acetone, H_3C-CO-CH_3

Aldehyde group : It is the class of organic compound in which the -CHO group is attached to a hydrocarbon is known as aldehyde.

The general representation of aldehyde are, R-CHO.

For example : Ethanal , H_3C-CH_2-CHO

Ether group : It is the class of organic compound in which the oxygen is directly attached to the two alkyl group of carbon is known as ether.

The general representation of ether are, R-O-R^'.

For example : Dimethyl ether, H_3C-O-CH_3

Amine group : It is the class of organic compound in which the -NH_2 group is directly attached to the alkyl group of carbon is known as amine.

The general representation of amine are, R-NH_2.

For example : Ethylamine, H_3C-CH_2-NH_2

As per question, aldehyde is an example of an organic compound that contains an attached carbonyl group at the end of the carbon chain.

Hence, the correct option is, Aldehyde.

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Convert 8.19 x 10-14 moles of gold to atoms.
lesya692 [45]

Answer:

4.932018 × 10¹⁰ atoms

Explanation:

Recall that:

1 mole = 6.022 × 10²³ atoms

To change 8.19× 10⁻¹⁴ moles to atoms;

Then, we have:

= (8.19× 10⁻¹⁴× 6.022 × 10²³ atoms)

= 4.932018 × 10¹⁰ atoms

6 0
3 years ago
Describe the difference between extensive and intensive properties
never [62]

Answer:

Intensive and extensive properties are both physical properties. However, intensive properties dont depend on the amount of matter present in a sample, whereas extensive properties do. Intensive properties only depend on the type of matter, such as color, temperature, or solubility. Extensive properties depend on the amount of matter, such as mass, volume or energy

Explanation:

3 0
3 years ago
6
tino4ka555 [31]

Answer : The correct option is, electron.

Explanation :

As we know that,

An atom is the smallest unit of a matter that consist of three subatomic particles which are electrons, protons and neutrons.

The protons and the neutrons are located inside the nucleus or the center of the nucleus where the mass of the an atom is concentrated.

The electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and the neutrons are neutral that means it has no charge.

According to the question, the electron subatomic particle found revolving around the nucleus.

Hence, the correct option is electron.

5 0
3 years ago
How many liters will 5.00 moles of oxygen occupy at STP?
Sveta_85 [38]

Answer:

1 mole of any gas at STP occupies 22.4 liters of volume. Using this information, the volume occupied by any number of moles (or grams) can be determined.

Explanation:

3 0
3 years ago
Instant cold packs, often used to ice athletic injuries on the field, contain ammonium nitrate and water separated by a thin pla
RSB [31]

<u>Answer:</u> The enthalpy change of the reaction is -27. kJ/mol

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 25.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{25.0mL}\\\\\text{Mass of water}=(1g/mL\times 25.0mL)=25g

To calculate the heat released by the reaction, we use the equation:

q=mc\Delta T

where,

q = heat released

m = Total mass = [1.25 + 25] = 26.25 g

c = heat capacity of water = 4.18 J/g°C

\Delta T = change in temperature = T_2-T_1=(21.9-25.8)^oC=-3.9^oC

Putting values in above equation, we get:

q=26.25g\tiimes 4.18J/g^oC\times (-3.9^oC)=-427.9J=-0.428kJ

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ammonium nitrate = 1.25 g

Molar mass of ammonium nitrate = 80 g/mol

Putting values in above equation, we get:

\text{Moles of ammonium nitrate}=\frac{1.25g}{80g/mol}=0.0156mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -0.428 kJ

n = number of moles = 0.0156 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-0.428kJ}{0.0156mol}=-27.44kJ/mol

Hence, the enthalpy change of the reaction is -27. kJ/mol

4 0
4 years ago
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