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2 years ago

Describe the difference between extensive and intensive properties

Chemistry

1 answer:

never [62]2 years ago

3 0

Answer:

Intensive and extensive properties are both physical properties. However, intensive properties dont depend on the amount of matter present in a sample, whereas extensive properties do. Intensive properties only depend on the type of matter, such as color, temperature, or solubility. Extensive properties depend on the amount of matter, such as mass, volume or energy

Explanation:

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Which of the following is true about a compound and its elements?

BaLLatris [955]

They can change properties completely
They can be separated
They form a new set of elements and compounds
<span>The elements become part of the original compounds</span>

6 0

3 years ago

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Rutherfordium has atomic number of 84 how many protons and electrons does it have

valentina_108 [34]

84 protons and 84 electrons.

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3 years ago

In order to do multiple trials of an experiment, _____. A. change your hypothesis B. do the experiment more than once C. revise

Arisa [49]

B. do the experiment more than once

Explanation:

To do a multiple trials of an experiment, it is best to do the experiment more than once.

Experimental trials are mere replication of the procedures in an experiment.

Most hypothesis on which experiments are based must be repeatable.
When experiments are repeated through several trials, their accuracy is increased.
Multiple trials clearly makes it easy to make meaningful deductions from an experimental process.

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8 0

3 years ago

The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4

Snowcat [4.5K]

Answer:

$\Delta H^o _{rxn} = -2568.9 \ kJ$

$H = 350 JK^{-1}$

$T_{max} = 32.4 ^o C$

Explanation:

From the question we are told that

The reaction of cyclobutane and oxygen is

$C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}$

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

$\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]$

=> $\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]$

=> $\Delta H^o _{rxn} = -2568.9 \ kJ$

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as

$H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]$

=> $H = [ 4 * 37.1 + 6* 33.6 ]$

=> $H = 350 JK^{-1}$

From the question the initial temperature of reactant is $T_i = 25^oC$

Generally the enthalpy change( $\Delta H^o _{rxn}$ ) of the reaction is mathematically represented as

$|\Delta H^o _{rxn} |= H * (T_{max} -T_i)$

$2568.9 = 350 * (T_{max} -25)$

=> $\frac{2568.9 }{350} = T_{max} - 25$

=> $T_{max} = 32.4 ^o C$

4 0

3 years ago

Methane burns in oxygen to produce carbon dioxide and water. Which of the tollowing represents a preliminary, unbalanced equatio

WITCHER [35]

So first we need to know what the formulas are:

Methane: $CH_{4}$

Oxygen: $O_{2}$

Carbon Dioxide: $CO_{2}$

Water: $H_{2}O$

So then we follow the equation as specified in the question. Note that it does not need to be balanced, as the question states it wants the unbalanced equation:

$CH_{4}+O_{2}$ → $CO_{2}+H_{2}O$

This is the preliminary, unbalanced equation with the correct chemical formulas.

4 0

3 years ago