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andrew-mc [135]
2 years ago
14

What does the octet rule state about each atom in a chemical compounds outer most energy level?

Chemistry
1 answer:
n200080 [17]2 years ago
5 0

Answer:

B. The outer most occupied energy level has an octet of electrons.

D. None of the above.

C. A hydrogen molecule and hydrogen molecule.

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PLEASE HELP <br> C. Balance these fossil-fuel combustion reactions. (1 point)
Damm [24]

Answer:

C8H18(g) + 12.5O2(g) -> __8__CO2(g) + 9H2O(g) + heat

CH4(g) + _2___O2(g) -> ____CO2(g) + _2___H2O(g) + heat

C3H8(g) + _5___O2(g) -> _3___CO2(g) + __4__H2O(g) + heat

2C6H6(g) + __15__O2(g) ->  __12__CO2(g) + __6__H2O(g) + heat

Explanation:

I hope it helps!

7 0
3 years ago
Rank the following in terms of increasing ionization energy: Sulfur, oxygen, hydrogen, and fluorine.
Naily [24]

Answer:

Ranked from lowest to highest:

Sulfur - 999.6 kJ/mol

Hydrogen - 13.5984 kJ/mol

Oxygen - 13.6181 kJ/mol

Fluorine - 17.4228 kJ/mol

3 0
2 years ago
How does the electron transport chain use the high energy electrons from the krebs cycle?
Sliva [168]
They move through the membrane
7 0
3 years ago
A 110.0-mL sample of a solution that is 3.0×10−3 M in AgNO3 is mixed with a 230.0- mL sample of a solution that is 0.10 M in NaC
almond37 [142]

Answer:

[Ag⁺] = 0.0666M

Explanation:

For the addition of Ag⁺ and CN⁻, the (Ag(CN)₂⁻ is produced, thus:

Ag⁺ + 2CN⁻  ⇄  Ag(CN)₂⁻

Kf = 1x10²¹ = [Ag(CN)₂⁻] / [CN⁻]² [Ag⁺]

As initial concentrations of Ag⁺ and CN⁻ are:

[Ag⁺] = 0.110L × (3.0x10⁻³mol / L) = 3.3x10⁻⁴mol / (0.110L + 0.230L) = 9.7x10⁻⁴M

[CN⁻] = 0.230L × (0.1mol / L) = 0.023mol / (0.110L + 0.230L) = 0.0676M

The equilibrium concentrations of each compound are:

[CN⁻] = 9.7x10⁻⁴M - x

[Ag⁺] = 0.0676M - x

[Ag(CN)₂⁻] = x

<em>Where x is reaction coordinate</em>

Replacing in Kf formula:

1x10²¹ = [x] / [9.7x10⁻⁴M - x]² [0.0676M - x]

1x10²¹ = [x] / 6.36048×10⁻⁸ - 0.000132085 x + 0.06954 x² - x³

-1x10²¹x³ + 6.954x10¹⁹x² - 1.32085x10¹⁷ x + 6.36x10¹³ = x

-1x10²¹x³ + 6.954x10¹⁹x² - 1.32085x10¹⁷ x + 6.36x10¹³ = 0

Solving for x:

X = 9.614x10⁻⁴M

Thus, equilibrium concentration of Ag⁺ is:

[Ag⁺] = 0.0676M - 9.614x10⁻⁴M = <em>0.0666M</em>

6 0
2 years ago
2022
Lapatulllka [165]

Answer:

OOO

Explanation:

OOOOOO

8 0
2 years ago
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