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3 years ago

Answer this with process and details plz thanks

Mathematics

1 answer:

BaLLatris [955]3 years ago

4 0

First part your answer is 8 second part is c.

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The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 vari

kenny6666 [7]

Let us assume the width of the rectangle = w
Let us assume the length of the rectangle = l
Then
l = 2w
Also
Perimeter of the rectangle = 2 (l + w)
24 = 2 (2w + w)
24 = 2 (3w)
24 = 6w
w = 24/6
= 4 inches
Now
The length of the rectangle = 2w
= 2 * 4 inches
= 8 inches
So the length of the rectangle is 8 inches and the width is 4 inches.

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3 years ago

What requirements must be met by a mathematical system in order to be a field?

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Answer:

Step-by-step explanation:

n mathematics, a set having an addition that must be commutative, and associative, and a multiplication that must be associative

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3 years ago

If a sprinkler waters 1 over 12 of a lawn in 1 over 2 hour, how much time will it take to water the entire lawn?

DIA [1.3K]

12 hours because if it’s one over 12 you need 12 hours to make the whole lawn

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3 years ago

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Which is a chord of circle P?

Zielflug [23.3K]

Answer:

Step-by-step explanation:

A chord is a line that joins two points on the outside of the circle

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3 years ago

a local businesses bought a square ploy of land. the sides of the lot measure 32 feet on each side. he decides to split the lot

san4es73 [151]

Answer:

Approximate length of the diagonal fencing needed is 45.25 cm.

Step-by-step explanation:

Here, each side of the square shaped land = 32 ft

Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.

<u>In the triangle:</u>

Base side of the triangle = 32 cm

Perpendicular length of the triangle = 32 cm

Let us assume the hypotenuse of the triangle = k cm

⇒The length of the diagonal in the square = k cm

by <u>PYTHAGORAS THEOREM</u> in a right angled triangle:

$(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}$

⇒ $(32)^2 + (32)^2 =k^2\\or, k^2 = 1024 + 1024 = 2048\\\implies k = \sqrt{2048} = 45.25$

or, k = 45.25 cm

Hence,the approximate length of the diagonal fencing needed to fence the square land is 45.25 cm.

6 0

3 years ago