4 years ago

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Physics

2 answers:

Galina-37 [17]4 years ago

4 0

Electrons are found in shells or orbitals that surround the nucleus of an atom

olga55 [171]4 years ago

3 0

All electrons are found in the outer shells orbiting the nucleus. Hope this helps!

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Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge

asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

$E =\dfrac{kq}{r^2}$

$q =\dfrac{Er^2}{k}$

inserting all the values

$q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}$

q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

4 0

4 years ago

Use your understanding of heat loss to ESTIMATE the cost of the lost energy through one standard window during an average summer

miskamm [114]

Answer:

The cost of energy is $ 0.34.

Explanation:

The energy is the capacity to do work.

The energy is a scalar quantity and its SI unit is Joule.

The commercial unit of energy is kWh.

Cost of 1 kWh energy = $ 0.17

energy loss by standard window is 2 kWh .

So, the cost of lost of energy is

Cost = $ 0.17 x 2 = $ 0.34

3 0

3 years ago

A block of aluminum at a temperature of T1 = 32 degrees C has a mass of m1 = 12 kg. It is brought into contact with another bloc

Mariulka [41]

Answer: $T=21.33 ^{\circ}$

Explanation:

Given

mass of First Block $m_1=12 kg$

Temperature $T_1=32^{\circ}$

mass of second block $m_2=0.5 m_1=6 kg$

Temperature $T_2=9^{\circ}$

Heat capacity of aluminium c=899 J/kg-K

Final Temperature acquired by both blocks at steady state

Heat loss first block =Heat gain by second block

$m_1\times c\times (32-T)=m_2\times c\times (T-9)$

$12\times 899\times (32-T)=6\times 899\times (T-9)$

$2\times 32=3T$

$T=\frac{64}{3}=21.33 ^{\circ}$

5 0

3 years ago

What is the bending of a wave around a barrier?

Mamont248 [21]

That's wave 'diffraction'.

3 0

4 years ago

Angelina_Jolie [31]

I am very sorry I don’t know

7 0

4 years ago