The amount of current passing through the point is 1 A
The amount of current passing through the point can be calculated using the formula below.
⇒ Formula:
- Q = i/t......................... Equation 1
⇒ Where:
- Q = Charge
- i = current
- t = time.
⇒ Make "i" the subject of the equation.
- i = Qt....................... Equation 2
From the question,
⇒ Given:
- Q = 1000 millicoulombs = 1 coulombs
- t = 1 seconds. (Assuming the time is 1 seconds)
⇒ Substitute these values into equation 2
Hence, The amount of current passing through the point is 1 A.
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Answer:
The new intensity decreases by a factor of 16.
Explanation:
The intensity of sound wave is given by :

P is power
A is area

or
, r is distance from the source
If the distance from the source is increased by a factor of 4, r' = 4r
So,

So, the new intensity decreases by a factor of 16.
Answer:
Neptune is approximately 41 times as far from the sun as Venus
Explanation:
Estimate = distance of Neptune from the sun ÷ distance of Venus from the sun = 4.5×10^9 ÷ 1.18×10^8 = 40.9 (approximately 41)
Answer:
Explanation:
This problem can be solved easily if we represent velocity in the form of vector.
The velocity of 351 was towards easterly direction so
V₁ = 351 i
The velocity of 351 was towards south west making - 48° with east or + ve x direction.
V₂ = 351 Cos 48 i - 351 sin 48 j
V₂ = 234.86 i - 260.84 j
Change in velocity
= V₂ - V₁ = 234.86 i - 260.84 j - 351 i
= -116.14 i - 260.84 j
acceleration
= change in velocity / time
(-116.14 i - 260.84 j )/ 1
= -116.14 i - 260.84 j
magnitude = 285.53 ms⁻²
Direction
Tan θ = 260.84 / 116.14 = 2.246
θ = 66 degree south of west .
Answer:
4
Explanation:
Refraction is the bending of light when it moves from one medium to another.
In the situation described:
- The average speed of light changes when it goes to another medium. The speed of light in water is less than in air.
- When velocity/speed changes, the index of refraction changes as well. Water's index is greater than in air.
- Since, speed changes, wavelength changes too.
- Only the frequency remains the same. The rates of vibration stays the same.
Correct choice is #4.