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Natali5045456 [20]
3 years ago
10

Why does Farm Bureau and other advocacy organization oppose any mandated labeling of biotech crops?

Physics
1 answer:
Step2247 [10]3 years ago
3 0

Answer:

I’m. Nog sure

Explanation:

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An electromagnetic radio wave is received by a transmitter before it is converted to a sound wave. The radio wave has a waveleng
lakkis [162]

Answer: The velocity is the wave traveling at before the transmitter converts it to a sound wave is 2.99\times 10^8 m/s

Explanation:

Wavelength of the  electromagnetic wave = 23,076 m

Frequency of the wave = 13,000 Hertz

\text{Time period}=\frac{1}{Frequency}

Velocity=\frac{displacement}{Time}=\frac{\lambda}{\text{Time period}}=\lambda \times Frequency=23,076\times 13,000 Hertz=2.99\times 10^8 m/s

The velocity is the wave traveling at before the transmitter converts it to a sound wave is 2.99\times 10^8 m/s

8 0
3 years ago
Read 2 more answers
Un caballo parte del reposo y alcanza una velocidad de 15m/s en un tiempo de 8s. ¿ Cuál fue su aceleración y que distancia recor
Lemur [1.5K]

Answer: A 120 metros por segundo

Explanation: multiplicas la velocidad por el tiempo

7 0
3 years ago
20.0 Ω resistor and a 2.50 μF capacitor are connected in parallel with signal generator. The signal generator produces a sinusoi
Free_Kalibri [48]

Answer:

0.15A

Explanation:

The parameters given are;

R=20.0 Ω

C= 2.50 μF

V= 3.00 V

f= 2.48×10^-3 Hz

Xc= 1/2πFc

Xc= 1/2×3.142 × 2.48×10^-3 × 2.5 ×10^-6

Xc= 25666824.1

Z= 1/√(1/R)^2 +(1/Xc)^2

Z= 1/√[(1/20)^2 +(1/25666824.1)^2]

Z= 1/√(2.5×10^-3) + (1.5×10^-15)

Z= 20 Ω

But

V=IZ

Where;

V= voltage

I= current

Z= impedance

I= V/Z

I= 3.00/20

I= 0.15A

6 0
3 years ago
A charge of 2.00 μC flows onto the plates of a capacitor when it is connected to a 12.0-V potential source. What is the minimum
uysha [10]

To develop this problem we will apply the concept of energy conservation. For which the work carried out must be equivalent to the potential energy stored on the capacitor. We will start by finding the capacitance to later be able to calculate the energy and therefore the work in the capacitor

C = \frac{Q}{V}

Here,

C = Capacitance

V = Potential difference between the plates

Q = Charge between the capacitor plates

At the same time the energy stored in the capacitor can be defined as,

U = \frac{1}{2} CV^2

We will start by finding the value of the capacitance, so we will have to,

C = \frac{2\mu C}{12.0V}

C = 0.166\mu F

Finally using the expression for the energy we have that,

U = \frac{1}{2} CV^2

U = \frac{1}{2} (0.166\muF)(12.0V)^2

U = 11.0*10^{-6} J

Therefore the minimum amount of work that must be done in charging this capacitor is 11.0*10^{-6} J

8 0
4 years ago
Read 2 more answers
An apple falls out of a tree from a height of 2.3m. what is the impact speed of the apple
Anuta_ua [19.1K]

Answer:6.71 m/s

Explanation:

Given

Apple fall from a height of h=2.3 m  

We need to find the impact speed of apple which can be given by using

v^2-u^2=2gh  

where v=final velocity

u=initial velocity

h=Displacement

Assuming initial velocity to be zero

substituting the value we get

v^2-0=2\times 9.8\times 2.3  

v=\sqrt{2\times 9.8\times 2.3}  

v=6.71\ m/s  

5 0
3 years ago
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