Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.


Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W
Answer:
Lol, you should do Nate, Bobby, Cindy, Joe, and Beth
Jk, if you want to be series and probably not fail go for these:
If it wants types of small/average stars, then go with
Small star names:
OGLE-TR-122B
Gliese 229 B
TRAPPIST-1
Teegarden's Star
Luyten 726-8 (A and B)
Proxima Centauri
Wolf 359 111400
Ross 248
Barnard's Star
CM Draconis B
Ross 154 167000
CM Draconis A
Kapteyn's Star
Given: Heat Qout means useful work = 2800 J
Heat Qin = 8900 J
Required; Efficiency = ?
Formula: Efficiency = Qout/Qin = x 100%
= 2800 J/8900 J = 0.3146 X 100 %
Efficiency = 31.46%
Answer:
a. 2.4 ×109 N ⋅ m2/s
b. 48.3 N⋅s /m2
c. 8.00×104W
Explanation:
See Attached file for explanation