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steposvetlana [31]
3 years ago
10

A bag contains 5 purple buttons, 12 blue buttons and 3 green buttons. A single button is randomly chosen.

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

60%

Step-by-step explanation:

5+3+12=20

20 = 1/5 of 100

12 x 5 = 60

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Solve #1 pls, I need to find the shortest side, median side, and longest side
Lisa [10]

Answer:

Shortest side = 39 cm.

Median side = 65 cm.

Longest side = 91 cm.

Step-by-step explanation:

The perimeter in total is 195 cm. The ratio of the sides are 3 : 5 : 7.

First, find how much parts there are as a whole, by combining the ratios:

3 + 5 + 7 = 15 parts.

Divide the total of parts from the total measurement:

195/15 = 13

Each part has the measurement of 13 cm.

1 part = 13 cm.

Use the following ratio to solve for each of the sides:

Shortest side: 3

3 x 13 = 39

Shortest side = 39 cm.

Median side: 5

5 x 13 = 65

Median side = 65 cm.

Longest side: 7

7 x 13 = 91

Longest side = 91 cm.

Check. Combine all side measurements together. They should equal 195:

39 + 65 + 91 = 195

(39 + 65) + 91 = 195

(104) + 91 = 195

195 = 195 (True).

~

8 0
4 years ago
What is 4.8x ten to the power of 8
dangina [55]
480,000,000 (480 million)
3 0
3 years ago
What is the greatest common factor of the terms in the polynomial 8xt – 4х – 18x??
mariarad [96]

2x

so...

2x (4t - 2 - 9)

2x (4t -  11)

Hope this helped!

~Just a girl in love with Shawn Mendes

3 0
3 years ago
Read 2 more answers
with reference to a universal set, the inclusion of a subset in another is relation which is a) symmetric only b) transitive onl
Vlad [161]

Answer:

D?

Step-by-step explanation:

I think it is D since a universal set would only be {1,2,3,4,5,6,...} and the subset would not satisfy any of the conditions of symmetric, transitive, and reflexive.

5 0
3 years ago
Find the critical numbers sin^2x+cosx 0 < x< 2pi
ryzh [129]
\bf sin^2(x)+cos(x)\iff [sin(x)]^2+cos(x)\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=2sin(x)cos(x)-sin(x)\implies 0=2sin(x)cos(x)-sin(x)
\\\\\\
0=sin(x)[2cos(x)-1]\implies 
\begin{cases}
0=sin(x)\\
sin^{-1}(0)=\measuredangle x\\
\pi \\
----------\\
0=2cos(x)-1\\\\ \frac{1}{2}=cos(x)\\\\ cos^{-1}\left( \frac{1}{2} \right)=\measuredangle x\\\\ \frac{\pi }{3},\frac{5\pi }{3}
\end{cases}
5 0
3 years ago
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