What is the length of the shortest side of a triangle that has vertices at (4,6), (-2,0), and (-6,3)?

5/12 + 2/3 <br> Please help

AnnZ [28]

Answer:

The answer is 1 and 1/12 you can’t simplify the problem but this is the answer

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Write an inequality that represents the verbal expression. All real numbers less than 74

Zina [86]

Hey there!

<span>x<74

Hope this helps!
~Jurgen</span>

6 0

3 years ago

100000000000000000000000000000000000000000000000 X 100000000000000000000000000000000000000000000000

AlladinOne [14]

Take all the zero's away and multiply the numbers that are left.

which is 1*1=1 now add all of the zeros to that one which will turn it into

10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

which is the answer

8 0

3 years ago

Read 2 more answers

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)?

MaRussiya [10]

Answer:

x > -2.5

Step-by-step explanation:

1) 5.1 (3 + 2.2x) > -14.25 - 6 (1.7x + 4)

2) 15.3 + 11.22x > -14.25 - 10.2x - 24

3) 15.3 + 11.22x > -38.25 - 10.2x

4) 11.22x + 10.2x > -38.25 - 15.3

5) 21.42x > -53.55

6) x > -2.5

Alternate forms

x > -5/2x or x > -2 1/2

5 0

3 years ago