What is the length of the shortest side of a triangle that has vertices at (4,6), (-2,0), and (-6,3)?
1 answer:
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Answer:
H
Step-by-step explanation:
The parallel line BC divides the sides AD and AE in proportion, that is
=
, that is
=
( cross- multiply )
3AC = 8 ( divide both sides by 3 )
AC = = 2
, hence
AE = AC + CE
= 2 + 4 = 6
→ H