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Karolina [17]
4 years ago
7

The height that a properly inflated basketball bounces decreases exponentially by 27.8% with each subsequent bounce after the in

itial drop. A local basketball league tests the inflation of their basketballs by dropping them from a height of 6 feet. Which equation can be used to model the height of the basketball, H, after b bounces?
Mathematics
1 answer:
n200080 [17]4 years ago
3 0

Answer:

H (b) = 0.722^b(6)

Step-by-step explanation:

The first time the basketball bounces it reaches a height of (1-0.278)(6) = (0.722) (6).

The second time the basketball bounces it reaches a height of (0.722) (0.722) (6) = [(0.722) ^ 2] (6). Therefore, after b rebounds the height that the basketball will reach is given by:

H (b) = 0.722^b(6)

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<h3><u>Answer</u> :</h3>

See the attachment for better understanding.

<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u>: Length of string (AC) = 300ft

<u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u> </u>: Height of the kite from ground (AB)

:\implies\sf\:sin60^{\circ}=\dfrac{AB}{AC}

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:\implies\sf\:H=150\sqrt{3}

:\implies\:\boxed{\bf{\red{H\approx 260\:feet}}}

Hope it helps !

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