All categories

3 years ago

Decide what the best solution would be if you reach your lab table and find a broken beaker with liquid spilling out.

1 answer:

6 0

There are many safety precautions and rules you MUST follow during labs.
for this incident here is what you should do:
1)Notify your Instructor and partner
2) if the liquid is toxic (like not water or vinegar) then let your Instructor handle it properly, or follow your instructors orders (like if they say to put a towel over it or something like that)
3) Broken glassware, minus mercury thermometer, must be immediately cleaned up, do not use your bare hand, always wear gloves.
4)dispose of the broken glass properly and clean the liquid up (unless it is harmful, then let your instructor do it)

You might be interested in

A certain reaction is endothermic in the forward direction. The reaction has less moles of gas on the product side. Which of the

xxMikexx [17]

It would have to increase pressure... but I don’t see that option here..?

6 0

3 years ago

The balanced equation below shows the products that are formed when butane (C4H10) is combusted. 2C4H10 + 13O2 mc009-1.jpg 8CO2

Verizon [17]

The correct answer would be option 1. The mole ratio of butane to carbon dioxide is 1:4. Looking at the balanced chemical reaction, we see that we need 2 moles of butane to produce 8 moles of carbon dioxide. So, it is 2:8. Simplifying this by dividing both to 2, we have 1:4.

6 0

2 years ago

Read 2 more answers

What is the pH of a solution of RbOH with a concentration of 0.86 M? Answer to 2 decimal places

lubasha [3.4K]

Answer:The pH of the solution is given by pH=−log([H3O+])

Explanation:so you can't use

−

log

(

0.150

)

because that's the concentration of the hydroxide anions,

−

, not of the hydronium cations,

. In essence, you calculated the

pOH

of the solution, not its

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce hydroxide anions in a

mole ratio.

NaOH

(

)

→

(

)

−

(

)

So your solution has

[

−

]

[

NaOH

]

0.150 M

Now, the

pOH

of the solution can be calculated by using

pOH

−

log

(

[

−

]

)

−−−−−−−−−−−−−−−−−−−−

In your case, you have

pOH

−

log

(

0.150

)

0.824

Now, an aqueous solution at

∘

has

pH + pOH

−−−−−−−−−−−−−−so you can't use

−

log

(

0.150

)

because that's the concentration of the hydroxide anions,

−

, not of the hydronium cations,

. In essence, you calculated the

pOH

of the solution, not its

Sodium hydroxide is a strong base, which means that it dissociates completely in aqueous solution to produce hydroxide anions in a

mole ratio.

NaOH

(

)

→

(

)

−

(

)

So your solution has

[

−

]

[

NaOH

]

0.150 M

Now, the

pOH

of the solution can be calculated by using

pOH

−

log

(

[

−

]

)

−−−−−−−−−−−−−−−−−−−−

In your case, you have

pOH

−

log

(

0.150

)

0.824

Now, an aqueous solution at

∘

has

pH + pOH

−−−−−−−−−−−−−−

3 0

2 years ago

13. How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe(s) + I'(aq) 12(s) + Fe3+(aq)

Nat2105 [25]

Answer : The correct option is, (C) 6

Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

$Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)$

Half reactions of oxidation and reduction are :

Oxidation : $Fe(s)\rightarrow Fe^{3+}+3e^-$ ......(1)

Reduction : $2I^-(aq)+2e^-\rightarrow I_2$ .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : $2Fe(s)\rightarrow 2Fe^{3+}+6e^-$ ......(1)

Reduction : $6I^-(aq)+6e^-\rightarrow 3I_2$ .......(2)

The overall balanced chemical reaction will be:

$2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)$

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

5 0

2 years ago

The chemical bonding in sodium phosphate, Na3PO4, is classified as:

fiasKO [112]

<span>Ionic bonding between sodium and phosphate ions.</span>

7 0

2 years ago

Read 2 more answers