Find length and width .the lenght is 10 times as long as the width.P=308
1 answer:
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The correct answer is: [A]: " 6 to the power of (1 over 6) " .
Explanation:
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√ [(∛6)] = √ [6⁽¹/³⁾ ] = [6⁽¹/²⁾ ] ⁽¹/³⁾ = 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) = ???? ;
<u>Note</u>: ;
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→ 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) ;
= 6^ ( ⁽¹/⁶⁾ ) ;
→ which is: Answer choice: [A]: " 6 to the power of (1 over 6) " .
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Answer:
The intensity of the first earthquake is 6.31 times the second one
Step-by-step explanation:
The given formulae is M=log()
Here for both the earthquakes the value of S is same.
Let the Intensity of the first earthquake be I1 and the second be I2.
Given M1=7.5
M2=6.7
Now M1=log()------1
M2=log()-----2
Now subtract 1 and 2 we get
M1-M2=log()
I1/I2=
I1=I2(
I1=I2*6.31