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3 years ago

Find length and width .the lenght is 10 times as long as the width.P=308

1 answer:

8 0

<span>Width(height): x
length of rectangle: 10x
perimeter: width +width +length +length = 308 inches
or ------- 2width+2length=308
2x+2(10x)=308
2x+20x=308
22x=308</span>

<span>
x=14 the width is 14 inches
length:
10x
10*14
140 inches
ANSWER:
Length:140 inches
Width: 14 inches</span>

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3 years ago

The sum of two positive numbers is 588. minimize the sum of the first and three times the second

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Answer:

{587, 1}

Step-by-step explanation:

The sum will be minimized when the second number is as close to zero as is allowed. If the numbers must be positive integers, the sum is minimized when the numbers are {587, 1}.

If the numbers may be real numbers, then the values that minimize the sum are {588-, 0+}

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2 years ago

a six sided number cube has faces with the numbers 1 through 6 marked on them. what is the probability that a number less than 3

mars1129 [50]

Answer:

Step-by-step explanation:

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1 year ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

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2 years ago

the Andersons kept track of the time they spent watching television. Part A wich bar diagram represents the number of hours the

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Part A:

Part B:

$\begin{gathered} 4\frac{5}{6}=\frac{29}{6} \\ 3\frac{4}{6}=\frac{11}{3} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}=\frac{17}{2}=8\frac{3}{6} \end{gathered}$

Part C:

$\begin{gathered} 3\frac{1}{6}=\frac{19}{6} \\ 2\frac{3}{6}=\frac{15}{6} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}+\frac{19}{6}+\frac{15}{6}=\frac{85}{6}=14\frac{1}{6} \end{gathered}$

Part D:

$\frac{17}{2}-\frac{17}{3}=\frac{17}{6}=2\frac{5}{6}_{}$

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1 year ago