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lubasha [3.4K]
3 years ago
13

Heeeeeeeellllllllllppppppppppppp plz i nned help

Mathematics
1 answer:
torisob [31]3 years ago
6 0

Answer:

Step-by-step explanation:

This is a ratio problem. there are 20 Blonde Teachers, and 12 brown haired teachers. The fraction is 12/20. We can simplify this fraction to 3/5. for every 3 brown haired Teacher, there is 5 other blonde hair teachers.

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the average cost of regular gasoline in north carolina increased by 73% from 2006 to 2007. If the average cost of a gallon of ga
mash [69]
You would need to do 2.069+73% which would get you 3.57937
5 0
3 years ago
4(x - 1) = - 4 + 4x plz
N76 [4]
4(x-1)=-4+4x
4x-4=-4+4x
-4x -4x
-4=-4

Not sure what the problem was asking, but it’s solvable!
3 0
3 years ago
Read 2 more answers
Harvey walks 45 feet in 8.5 seconds. What is Harvey's rate in feet per<br> second?
lilavasa [31]

The answer is : 5.29411764706

The answer when rounded:  5.29 or 5.3

I found the answer by simply dividing 45/8.5 - Remember that per means division!

6 0
2 years ago
Please help. Thank you.
Marysya12 [62]

The answer would be 24pi inches.

You can find this by using the formula for a circumference and plugging in the value of the radius.

C = 2pi*r

C = 2pi * 12

C = 24pi

4 0
2 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
2 years ago
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