Don't repost because somebody will answer (probably)
we got some points
normally it is like
y=mx+b
find m and x
if we assume they are in a straight line
m is slope and b is y intercept
ok so we see the slope betwee (6,11) and (3,5) is 2
because slope between (x1,y1) and (x1,y1) is (y2-y1)/(x2-x1)
y=2x+b
if we solve for b we get
hmm
5=2(3)+b
5=6+b
-1=b
y=2x-1
so double x and minus 1 to get y
10*2=20, 20-1=19
23=2x-1
24=2x
12=x
the missing points are 19 on right side and 12 on left
rule is y=2x-1 or
2x-y=1
We can write this as
(x - 5)^2 + (y + 3)^2 = r^2
where r = radius
Plugging in the point (2,5) we have
(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is
(x - 5)^2 + (y + 3)^2 = 73
Look up this site called calculator soup it gives great answers
Answer:
-2(x^2+2)
Step-by-step explanation:
1. x^2-3x^2-4
= -2x^2-4
2. -2(x^2+2) factor completely :)
<span>The car will stop in 140.625 ft
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