This gap between user-designer communications <span>can cause a good project to go bad i</span>f the user is not able to process what is required to be fixed in order for the project to run smoothly. The user may have one way of fixing something while the designer has another. In this case, the designer understands how the project fully works while the user does not and this may end up compromising the whole project.
The law that “designers are not users” and “users are not designers” should always be followed.
Answer:
Where are the choices?
Thanks for adding the choices at the comment secion
- 2D animation
- 3D animation
- Stop Motion
- Celluloid animation
A- Celluloid Animation
It is because many people want to be perfect just at the start, but there is always room to improvement, but people don't accept that, so they don't want to be better than what they are already, so the don't revise themselves or anything.
Answer:
Explanation:
Known Variables A = max Daily Rentals
X = Damaged helmets %
lets find the formula to calculate Helmets per location :taking 1st row as an example.
412 = B - (B*13/100)
412 = (100B-13B)/100
412*100 = 87B
B= 412*100/87
Hence, the generic formula becomes : B= A*100/(100-X)
Applying the same formula for each row and then using ROUND function of excel to round off the digits
=ROUND(number,digits) where number is the number you would like to round off and the digits is the number of decimal digits for it to round off. Since we want natural numbers in our example, we will be using digits as 0.
Explanation:
See attached pictures also.
Answer:
// program in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variable
int inp_month;
cout<<"Enter month:";
// read month
cin>>inp_month;
// if month is february
if(inp_month==2)
cout<<"Number of days in month:28"<<endl;
// if month is 4 or 6 or 9 or 11
else if(inp_month==4||inp_month==6||inp_month==9||inp_month==11)
cout<<"Number of days in month:30"<<endl;
else
// for others month
cout<<"Number of days in month:31"<<endl;
return 0;
}
Explanation:
Read month from user and assign it to variable "inp_month".If month is 2 then there is 28 days in the month.If input month is 4 or 6 or 9 or 11 then there is 30 days in the month.For other month there will be 31 days in month.We assume there is no leap year.
Output:
Enter month:4
Number of days in month:30
