All categories

2 years ago

What is the multiplicative inverse of 2?

Mathematics

1 answer:

andrew-mc [135]2 years ago

5 0

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Given a number n then the multiplicative inverse is $\frac{1}{n}$

The product of a number and it's multiplicative inverse = 1

Given 2, then multiplicative inverse is $\frac{1}{2}$

You might be interested in

Simplify the expression (8+i)(2+7i)

Rus_ich [418]

Given : (8 + i)(2 + 7i)

⇒ (8 × 2) + (8 × 7i) + (i × 2) + (i × 7i)

⇒ 16 + 56i + 2i + 7i²

We know that i² = -1

⇒ 16 + 58i + 7(-1)

⇒ 16 + 58i - 7

⇒ 9 + 58i

4 0

2 years ago

The consecutive angles of a rectangle are supplementary

stepan [7]

Answer:c

Step-by-step explanation:

5 0

3 years ago

Find the slope of the line passing through the points (-9, -3) and (7. - 7),<br> und<br> X

ad-work [718]

Answer:

-11/2

Step-by-step explanation:

because that's the answer

6 0

2 years ago

Suppose that $9500 is placed in an account that pays 8% interest compounded each year.

Blababa [14]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}$

6 0

2 years ago

Evaluate the expression 43/23

ivanzaharov [21]

That would be 43 divided by 23 which would equal 1.8695

3 0

3 years ago