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Sholpan [36]
3 years ago
13

What is the multiplicative inverse of 2?

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

\frac{1}{2}

Step-by-step explanation:

Given a number n then the multiplicative inverse is \frac{1}{n}

The product of a number and it's multiplicative inverse = 1

Given 2, then multiplicative inverse is \frac{1}{2}

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Jackson is 5 years old. His brother Micah is 20 years older than him. Which equation represents Micah's age in comparison with J
mina [271]

Answer:

M=5+20

Step-by-step explanation:

I’m using M for representing Micah’s age.

This would represent Micah’s age because it says that Micah is 20 years older than Jackson, who is 5. Therefore, you would just need to add 5 and 20 together. Micah is 25 years old.

8 0
3 years ago
The Brown family bought 9 bags of cookies. Each bag had 16 cookies. They have since eaten 26 of the cookies. How many cookies do
grigory [225]

Answer:

118 cookies

Step-by-step explanation:

1. 9x 16  

2.144-26

And then get 118! Have a nice day YW!!!!!???

3 0
2 years ago
HELP PLEASE!!!!!!!!!!!!!!! ASAP
evablogger [386]

AnswerASK THE TEACHER

Step-by-step explanation:

8 0
3 years ago
A pumpkin is thrown out of a window that is 4 feet high with an upward velocity of 14. When will the pumpkin hit
Gnom [1K]

Answer:

Step-by-step explanation:

Given

Height H = 4 feet

Velocity = 14ft/s

Required

Time the pumpkin will hit the ground

Using the equation of mottion

H = ut + 1/2gt²

4 = 14t + 1/2(9.8)t²

4 = 14t + 4.9t²

4.9t²+14t-4 = 0

t = -14±√196+16(4.9)/2(4.9)

t = -14±√196+78.4/2(4.9)

t = -14±16.57/9.8

t = -14+16.57/9.8

t = 2.57/9.8

t = 0.2seconds

7 0
3 years ago
Find the sum of all coefficients in the following binomial expansion.
natima [27]

Answer:

We can find the sum of all the coefficients by substituting all the variables in the expansion with one.

a. u=1,v=1

sum=(2*1+1)^{10}=3^{10}

b.u=1,v=1

sum=(2*1-1)^{10}=1

c.u=1,v=1

sum=(2*1-3*1)^{11=-1

d.u=1,v=1

sum=(1-3*1)^{11}=-2^{11

e.i=1

sum=(1+1)^{10=2^{10

f.i=1

sum=(1-1)^{10=0

g.i=1

sum=(1+1)^{200=2^{200

h.i=1

sum=(1+1)^{201}=2^{201

7 0
3 years ago
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