Answer: 89
Step-by-step explanation:
check on google
Answer:
The answer is the fourth one!
=7c^2d-7c+4d-10
A. -3 < x < 1
b. x < = 4 or x > = 6
y = mx + b
y = 2x + 1
y - y₁ = m(x - x₁)
y - 4 = 2(x - 5)
y - 4 = 2(x) - 2(5)
y - 4 = 2x - 10
+ 4 + 4
y = 2x - 6
<h3>
Answer: (-infinity, 7]</h3>
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Explanation:
The first interval (-infinity, 3) describes any number less than 3, so we can write x < 3 in short hand (where x is the unknown number).
The second interval (-1, 7] means we start at -1 and stop at 7. We do not include -1 but include 7. So we say that
(ie x is between -1 and 7; exclude -1, include 7)
If you were to graph each ona number line, you would see that the too intervals have overlapping parts. The right most edge extends out as far as x = 7. There is no left most edge as it goes onforever that direction.
Therefore, the to intervals combine to get
which turns into the interval notation answer of (-infinity, 7]
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It might help to think of it like this: x < 3 and
say "x is some number that is less than 3, or it is between -1 and 7". So x could be anything less than 7, including 7 itself.