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Mariana [72]
3 years ago
11

Write two ways you could use to find 5+8

Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0
Well, you can do, 4+9, and 5+9, or, instead of 5+9, maybeeeee, 6+7!
Tatiana [17]3 years ago
4 0
5+9 thats one way....buts theres alot of ways to get 13
                                                                                        Hope it helps

                                                                                                                 <3
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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
How do you solve<br> 25n=70
alisha [4.7K]
You want to do to one side the same thing you do to the other side.

In order to get the n by itself you divide the 25n by 25. But in order to not change the answer you need to do the same to the 70.

\frac{25n}{25} =  \frac{70}{25}

so n=\frac{70}{25} which can be reduced to \frac{14}{5}

so n=\frac{14}{5}
5 0
3 years ago
What is the area of the polygon?
Elenna [48]
Hello,

Answer C
13*(12-3)+3*10=147

6 0
3 years ago
Local hamburger market are (as percentages of all hamburgers sold): 23 percent, 22 percent, 18 percent, 12 percent, 11 percent,
Tamiku [17]
The top 4 firms have (23 +22 +18 +12)% = 75% of the market.

The 4-firm concentration ratio is 0.75 or 75%.
3 0
3 years ago
Did you ever get the answers ?
RSB [31]

Answer:

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8 0
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