The first thing we must do for this case is to calculate the scale factor.
For this, we make the relationship between two parallel sides.
We have then:

Substituting values we have:

We are now looking for the value of AB
We have then:

Substituting values:

Answer:
The scale factor is:

The value of AB is:

Answer:
.a^3-2a+3a^2+1\right)and\left(3-2a+a 2\ri
Step-by-step explanation:
pls brainliest
that's-- on edmentum isn't it?
first pair is -3
second pair is -2
third pair is 0'
and the last one is 5
that what i think it is .....????
Answer:
2^-3
Step-by-step explanation:
4^(-6)*4^(4)*(2^(3)*2^(-4))^(-1)
2^-3
Answer:
A -- the curves that are not parabolas
Step-by-step explanation:
The inverse relation will only be a function if it passes the vertical line test: a vertical line cannot intersect the curve at more than one point.
A "half-parabola" can have an inverse function.
A parabola will have an inverse relation that is not a function. When x-values are repeated, as "goes through (5, 2) and goes through (5, -2)", the relation is not a function.
The graph that shows inverse functions is attached. A function and its inverse are mirror images of each other in the line y=x.