The net for a triangular prism consists of
2 identical triangles, here all nets have sides 5,12, and 13.
3 rectangles, all with a common dimension: the height H=14 of the prism.
Each of the 3 rectangles should have dimensions
H=14 plus one of the following:
each of 5, 12, 13 corresponding to one side of the base (triangle).
So the dimensions of the rectangles are
5x14, 12x14, 13x14
And dimensions of the triangles are
5,12 and 13.
The total surface area is therefore
(5+12+13)*14 + 2*(5*12/2)
=420+60
=480.
There is only one net that satisfies this condition.
Answer:
x=35
'x-10'=25 degrees
'x'=35 degrees
The last one is 120 degrees
Step-by-step explanation:
A straight line is 180 degrees
180-60=120
2x+110=180
2x=70
x=35
Answer:
All three.
Step-by-step explanation:
All three of these ratios are equivalent to 15:5. Here's how:
Let's look at the first ratio, 9:3. Did you notice something common? 3 x 3 = 9. 9/3 = 3. 5 x 3 = 15. 15/3 = 5. Both of these numbers are divisible by 3, so these ratios are equivalent.
Second. 6:2. 2 x 3 = 6. 6/3 = 2. 5 x 3 = 15. 15/3 = 5. See the similarity? The same applies to the next problem, number three, although it does slightly differentiate.
Third, 3:1. See, here, since the ratio is smaller than the problem, we can't multiply, since this ratio is smaller than the original number. But, it's still the same thing. A ratio is a number that compares a value to another value. This means that 3:1 is 3 compared to one. Now, let me clarify. 15:5. 3:1. These are the exact same values, except they are just written in a different form, and simplified. Since 5 x 3 = 15, we know that we can divide 15 evenly by 5, which makes it 3, and divide 5 evenly by 5, which equals one. So here we have our answer for the third problem. 5:1.
Ratios are basically division, except simplified. Every single ratio problem works this way. Once you get the hang of it, it's immensely easy. Hope this helped!
The last one
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Answer: I wrote the answer in docs so here is the pic for the whole equation i explained it too! I hope this helped
