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Alinara [238K]
4 years ago
10

If Earth was 10 times farther away from the sun than it is now, which planet would it be closest to? (Assume all the planets are

aligned with the sun and are on the same side of the sun.) Compare Earth's new distance to that planet. How far apart would they be in standard notation? How far apart in scientific notation? Show your work. Can y'all please give me the answer in km, Need answer asap. thx
Mathematics
1 answer:
damaskus [11]4 years ago
5 0

Answer:

Earth is now 1,495,978,700 km or 1.495 billion km which is just over Saturn's' 1.43 billion km

Step-by-step explanation:

Earth is this far from the son 149,597,870 km

149,597,870*10= 1,495,978,700 km

Mercury = 70 million km

Venus = 108 million km

Mars = 228 million km

Jupiter = 779 million km

Saturn =  1.43 billion km

Uranus = 2.88 billion km

Neptune = 4.50 billion km

Pluto = 5.91 billion km

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Find the area of the rectangle. Show your work!
Nesterboy [21]

3x^2 - 7x - 20

use FOILING

4 0
3 years ago
Solve for x in simplest form (again) You don't need to write out the work for me, you can jus write down the answer you got.
FromTheMoon [43]

Answer:

x = 40/21

Step-by-step explanation:

This should be the right answer...

5 0
3 years ago
Read 2 more answers
A mountain railway AB is of length 864m and rises at an angle of 120° to the horizontal.
Ainat [17]

Answer:

The height above sea level at <em>B</em> is approximately 1,604.25 m

Step-by-step explanation:

The given length of the mountain railway, AB = 864 m

The angle at which the railway rises to the horizontal, θ = 120°

The elevation of the train above sea level at <em>A</em>, h₁ = 856 m

The height above sea level of the train when it reaches <em>B</em>, h₂, is found as follows;

Change in height across the railway, Δh = AB × sin(θ)

∴ Δh = 864 m × sin(120°) ≈ 748.25 m

Δh = h₂ - h₁

h₂ = Δh + h₁

∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m

The height above sea level of the train when it reaches <em>B</em> ≈ 1,604.25 m

4 0
3 years ago
The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 intersect to form the sides of a right triangle. Find the perimeter and area
tino4ka555 [31]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Determining the perimeter and area of the triangle giving line equation</h3>

In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

The points of intersection of the line are;

(x₁, y₁) = (- 0.4, 5.2),

(x₂, y₂) = (-0.8, 4.4),

(x₃, y₃) = (0, 4)

Determine the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

Determine the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

<u>For the area</u>

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/12010318

#SPJ1

3 0
2 years ago
Evaluate 6²-7²+8²-9²+..+998²-999²​
Llana [10]

Answer:

-499,485.

Step-by-step explanation:

We can transform this to an arithmetic series by  working it out in pairs:

6^2 - 7^2 = (6-7)(6+7) = -13

8^2 - 9^2 = (8-9)*8+9) = -17  

10^2 - 11^2 = -1 * 21 = -21 and so on

The common difference is -4.

The number of terms in this series  is (998 - 6) / 2 + 1

= 992/2 + 1 = 497.

Sum of n terms of an A.S:

= n/2 [2a1 + (n - 1)d  

Here a1 = -13, n = 497, d = -4:

Sum = (497/2)[-26 - 4(497-1)]

= 497/2 * -2010

= -499,485.

3 0
3 years ago
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