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trasher [3.6K]
3 years ago
6

How many calories are needed to raise the temperature of 25 grams of water form 50°C to 70°C. The specific heat of water is

Chemistry
2 answers:
Papessa [141]3 years ago
7 0

Answer:

500 cal

Explanation:

Gala2k [10]3 years ago
4 0

Answer:

500 cal

Explanation:

m=25g,c=1cal/g, change in temperature=70-50,20 degree Celsius Q=?

using formula Q=mxcx change in theta

Q=25x1x20

Q=500cal

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A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0
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<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

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n_1M_1V_1=n_2M_2V_2

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n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

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Putting values in above equation, we get:

2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

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Volume of solution = 1.00 L

Putting values in above equation, we get:

0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g

Hence, the mass of original oxalic acid sample is 6.75 grams

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The correct one is Respiratory Distress !!

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