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trasher [3.6K]
3 years ago
6

How many calories are needed to raise the temperature of 25 grams of water form 50°C to 70°C. The specific heat of water is

Chemistry
2 answers:
Papessa [141]3 years ago
7 0

Answer:

500 cal

Explanation:

Gala2k [10]3 years ago
4 0

Answer:

500 cal

Explanation:

m=25g,c=1cal/g, change in temperature=70-50,20 degree Celsius Q=?

using formula Q=mxcx change in theta

Q=25x1x20

Q=500cal

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Answer:

Kp = 0.049

Explanation:

The equilibrium in question is;

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E             3.3 - 2x    0.79 - x    2x

We are told 2x = partial pressure of SO₃ is 0.47 atm at equilibrium, so we can determine the partial pressures of  SO₂ and O₂ as follows:

p SO₂  = 3.3 -0.47 atm = 2.83 atm

p O₂ = 0.79 - (0.47/2) atm = .56 atm

Now we can calculate Kp:

Kp = 0.47² /[ ( 2.83 )² x 0.56 ] = 0.049 ( rounded to 2 significant figures )

Note that we have extra data in this problem we did not need since once we setup the ICE table for the equilibrium we realize we have all the information needed to solve the question.

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