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Amiraneli [1.4K]
3 years ago
15

Find the number of moles in 1.00 x 1023 atoms of chromium.

Chemistry
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

<h2>0.17 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

n =  \frac{1.00 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{1}{6.02}  \\   = 0.166112

We have the final answer as

<h3>0.17 moles</h3>

Hope this helps you

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The correct name for the N3- ion is a nitride ion.
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Which of the following groups in the periodic
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Elements of Group 1 and  group 2  in the periodic table contain elements so reactive that they are  never found in the free state

<u>Explanation</u>:

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3 years ago
Where do properties of matter come from?
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Answer:

Extensive or inextinsive and either physical or chemical

8 0
2 years ago
I have attached all the problems, but really if you just do one so I understand how to do it, that would be great!
Ivahew [28]

Answer:

Answer of question a is 345J.

Explanation:

In question a following is given in data:

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Solution:

Formula for Heat is :

Q=m x c x ΔT

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  • From the above formula all other questions can easily be solved from the same procedure.
4 0
3 years ago
Copper(II) fluoride contains 37.42% F by mass. Calculate the mass of fluorine (in g) in 55.5 g of copper(II) fluoride.
Mrac [35]

Answer:

There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride

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x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen

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Hence there are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.

5 0
3 years ago
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