The balanced chemical reaction for the complete combustion of C4H10 is shown below:
C4H10 + (3/2)O2 --> 4CO2 + 5H2O
The enthalpy of formation are listed below:
C4H10: -2876.9 kJ/mol
O2: none (because it is pure substance)
CO2: -393.5 kJ/mol
H2O: -285.8 kJ/mol
The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.
ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
= -<em>126.1 kJ</em>
Thus, the enthalpy of combustion of the carbon is -126.1 kJ.
Answer:
Molarity = 0.5 M
Osmolarity = 0.5 x 2 = 1 Osmpl.
Molecules of Cl2 = 6.02 x / 4= 1.505 x no. of molecules
Explanation:
If we add half mole in 1L volume than molarity will obviously be 0.5 M.
The osmolarity is molarity multiplies by number of dissociates of solute that for CaCl2 are 2. So, 2 x 0.5 = 1
Half will be molecules of Ca and half will be of Cl2 for 0.5M.
<u>Answer:</u>
<em>54.9 mg of the radioisotope are still active after 110 min.</em>
<u>Explanation:</u>
Half-life of F-18 is found to be 109.7 minutes
Rate constant
t = time taken = 110 minutes
[A] is the final quantity
is the initial quantity
Plugging the values and solving for [A]
[A] = 54.9 mg is the Answer
Answer:
2Fe + 8HCl =2 HFeCl4 + 3H2
Explanation:
Fe + HCl = HFeCl4 + H2
1Fe 1Fe
1H 3H
1Cl 4CL
2Fe + 8HCl =2 HFeCl4 + 3H2
2Fe 2Fe
8H 8H
8Cl 8CL