Answer:
standard entropy of vaporization of ethanol = 142.105 J/K-mol
Explanation:
given data
enthalpy of vaporization of ethanol = 40.5 kJ/mol = 40.5 × 
J/mol
entropy of vaporization of ethanol boiling point = 285 K
to find out
standard entropy of vaporization of ethanol
solution
we get here standard entropy of vaporization of ethanol that is expess as
standard entropy of vaporization of ethanol ΔS = 
.............1
here ΔH is enthalpy of vaporization of ethanol and T is temperature
put value in equation 1
standard entropy of vaporization of ethanol ΔS = 
standard entropy of vaporization of ethanol = 142.105 J/K-mol
It is an Alkene because it has a double bond, so it’ll have “ene” at the end. The simplest Alkene has 2 carbons.
2 carbons = “eth”
Look at that! Two carbons! It must be “ethene”
Answer:
ΔH = 180.6 kJ
Explanation:
Given that:
N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ
<u>2NO (g) + O2 (g) = 2NO2 (g) ΔH = -114.2 kJ </u>
N2 (g) + O2 (g) = 2NO (g) ΔH = ????
The subtraction of both equations would yield the unknown ΔH , therefore:
ΔH = 66.4 - ( - 114.2 kJ)
ΔH = 180.6 kJ
Answer:
choice 3
Explanation:
Hydrogen bonding occurs when a H is bonded to a highly electronegative atom like F. Towards the upper right corner, most atoms have high electronegativity and small atomic radii, according to periodic trends.
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Answer:
1. Fe + H2SO4 = FeSO4 + H2
iron + sulfuric acid = duretter + hydrogen
2. Mg + 2 HNO3 = Mg(NO3)2 + H2
Magnesium + nitric acid = magnesium nitrate +hydrogen
3. Zn + 2 HCl = ZnCl2 + H2
Zinc + hydrogen chloride= zinc chloride+ hydrogen
